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How can I remove a key from a dictionary?

By : Hima Bindu
Date : September 03 2020, 02:00 AM
I hope this helps you . delete! will remove a key-value pair from a dictionary if the key exists, and have no effect if the key does not exist. It returns a reference to the dictionary:
code :
julia> dict = Dict(1 => "one", 2 => "two")
Dict{Int64,String} with 2 entries:
  2 => "two"
  1 => "one"

julia> delete!(dict, 1)
Dict{Int64,String} with 1 entry:
  2 => "two"
julia> dict = Dict(1 => "one", 2 => "two");

julia> value = pop!(dict, 2)

julia> dict
Dict{Int64,String} with 1 entry:
  1 => "one"

julia> value = pop!(dict, 2)
ERROR: KeyError: key 2 not found
julia> dict = Dict(1 => "one", 2 => "two");

julia> value_or_default = pop!(dict, 2, nothing)

julia> dict
Dict{Int64,String} with 1 entry:
  1 => "one"

julia> value_or_default = pop!(dict, 2, nothing)
julia> dict = Dict(1 => "one", 2 => "two", 3 => "three", 4 => "four");

julia> filter!(p -> iseven(p.first), dict)
Dict{Int64,String} with 2 entries:
  4 => "four"
  2 => "two"

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Remove Keys in Dictionary and Store Values in a Dictionary of Lists

By : user2514880
Date : March 29 2020, 07:55 AM
it fixes the issue So I have a dictionary with "items" which has a list of dictionaries. I'm trying to restructure it to be a dictionary of "items" that has a list of lists that contain the values of the previous dictionary's keys. , It seems like operator.itemgetter is almost what you want:
code :
getter = operator.itemgetter('A', 'B', 'C', 'D')
data = {'items': [getter(dct) for dct in data['items']]}
>>> data = { 
...    "items": [ 
...            { "A": 0.00, "B": 2184.83, "C": "string", "D": "16122 " }, 
...            { "A": 0.00, "B": 5176.66, "C": "string", "D": "21216 " } 
...             ] 
...        }
>>> import operator
>>> getter = operator.itemgetter('A', 'B', 'C', 'D')
>>> data = {'items': [getter(dct) for dct in data['items']]}
>>> data['items'][0]
(0.0, 2184.83, 'string', '16122 ')
>>> data['items'][1]
(0.0, 5176.66, 'string', '21216 ')

Append, Remove, Edit a Dictionary Item from List of Dictionary

By : user3463557
Date : March 29 2020, 07:55 AM
around this issue How do I perform such task in a list of dictionary?
code :
lists = [{'firstname': 'John', 'lastname': 'Doe', 'color': 'red'}]

# update value to 30 
lists[0]["age"] = 30
# update value to smith
lists[0]["lastname"] = "Smith"
# finally delete using the del statement using the key
del lists[0]["color"]

[{'firstname': 'John', 'lastname': 'Doe', 'age': 30, 'color': 'red'}]
[{'firstname': 'John', 'lastname': 'Smith', 'age': 30, 'color': 'red'}]
[{'firstname': 'John', 'lastname': 'Smith', 'age': 30}]

Python dictionary: sum up numerical and remove 'None' values from nested dictionary and assign results to keys of first

By : Marquis Tan
Date : March 29 2020, 07:55 AM
may help you . It might be very simple but at the moment, I just don't find a solution for my problem. , Updated to reflect new question data:
code :
clean_pps = {k: sum(filter(None, v.values())) for k, v in list_of_pps.items()}

In python, how to remove duplicate values for a list of dictionary inside a dictionary?

By : Prawira Aditama
Date : March 29 2020, 07:55 AM
will be helpful for those in need You're nesting too much, just use a single dict for each scanid. I'm using setdefault here, but you can achieve a similar result with defaultdict too:
code :
data = ... # your original data 
scans = {}
for d in data:
    scans.setdefault(d['scanid'], {}).setdefault(d['ip'], []).append(d['port'])
print scans
{1000: {u'': [443]}, 
 1001: {u'': [80], 
        u'': [80], 
        u'': [80]}, 
 1002: {u'': [110, 31337]}}
from collections import defaultdict
scans = defaultdict(lambda: defaultdict(list))
for d in data:

How can I remove items from a dictionary while iterating throught the dicionary given a starting dictionary key in the l

By : adadad
Date : March 29 2020, 07:55 AM
seems to work fine I am trying to draw polylines from points I have in a dictionary as {OID:PointGeometry,,,}, I am trying to start at a given OID and find the nearest point stored in another dictionary. The second dictionary is exactly the same as the first only it is missing the first point being searched from in the first dictionary. While iterating through the dict I want to delete the points that have been drawn through from the dictionary so that lines don't overlap. 1 dictionary has 141 items the other 140 items. For some reason no points are being deleted and the loop only seems to iterate once. , You don't even need pointDict2. You could do the following:
code :
import math

startOid = ...
# While there are more elements to draw
while len(pointDict) > 1:
    shape = pointDict.pop(startOid)
    X = shape.centroid.X
    Y = shape.centroid.Y
    Z = shape.centroid.Z
    nextOid = None
    minSquaredDist = math.inf
    for otherOid, otherShape in pointDict.items():
        otherX = otherShape.centroid.X
        otherY = otherShape.centroid.Y
        otherX = otherShape.centroid.Z
        squaredDist = (X - otherX) ** 2 + (Y - otherY) ** 2  + (Z - otherZ) ** 2
        if squaredDist < minSquaredDist:
            minSquaredDist = squaredDist
            nextOid = otherOid
    minDist = math.sqrt(minSquaredDist)
    print minDist, nextOid
    startOid = nextOid
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