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How to build histogram in Julia

Date : September 05 2020, 11:00 PM
Does that help Looking for function to build histogram, something like: , You can use something like this:
code :
function partition(data, intervals)                                                                                
    ranges = intervals[1:end-1] .=> intervals[2:end]                                                               
    bins = [similar(data, 0) for _ in 1:length(ranges)]                                                                          
    for x in data                                                                                                  
        for (i, (a, b)) in pairs(ranges)                                                                           
            if a <= x < b                                                                                          
                push!(bins[i], x)                                                                                  
    return bins                                                                                                    
julia> partition([1.1, 1.2, 2.1, 2.1], 1:1:3)
2-element Array{Array{Any,1},1}:
 [1.1, 1.2]
 [2.1, 2.1]

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Getting a 2D histogram of a grayscale image in Julia

By : user2898840
Date : March 29 2020, 07:55 AM
seems to work fine hist also accepts a vector (or range) as an optional argument that specifies the edge boundaries, so
code :
hist(img_gld_gs, 0:256)

Histogram calculation in julia-lang

By : sunflowerdeath
Date : March 29 2020, 07:55 AM
should help you out As the person who wrote the underlying function: the aim is to get bin widths that are "nice" in terms of a base-10 counting system (i.e. 10k, 2×10k, 5×10k). If you want more control you can also specify the exact bin edges.

Histogram with log y axis in Julia Plots.jl

By : findLyon
Date : March 29 2020, 07:55 AM
seems to work fine The problem is that you have an axis range that goes to zero, which is -Inf in log space. There are a few ways to fix this, the easiest is probably to force a lower bound on the axis:
code :
using Plots; gr()
histogram(randn(1000), yaxis = (:log10, (1,Inf)))

Return the frequency in a bin of a 2D histogram in Julia

By : Sick N Sane
Date : March 29 2020, 07:55 AM
will help you I'm not 100% sure whether this is what StatsPlots is doing, but one approach could be to use StatsBase's histogram which works for N dimensions:
code :
using StatsBase, StatsPlots, Distributions

# Example data 
data = (randn(10_000), randn(10_000))

# Plot StatsPlots 2D histogram

# Fit a histogram with StatsBase
h = fit(Histogram, data)
x = searchsortedfirst(h.edges[1], 0.1)  # returns 10
y = searchsortedfirst(h.edges[2], 0.1)  # returns 11
h.weights[x, y] # returns 243

# Or as a function
function get_freq(h, xval, yval)
    x = searchsortedfirst(h.edges[1], xval)
    y = searchsortedfirst(h.edges[2], yval)
    h.weights[x, y]

get_freq(h, 1.4, 0.6) # returns 32

Doing a histogram from two sets of values (Julia 0.6.4)

By : Larry
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further You can use PyPlot for this (please not that it should be installed first)
code :
 using PyPlot
p = PyPlot.plt[:bar](x,y,width=25);
PyPlot.plt[:cla]()  #remember to clear the plot :-)
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