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Basic C Pointers

By : Dhaval Gohel
Date : September 12 2020, 11:00 PM
Hope this helps You do not need to have this line in your code if you just want to print the address of x.
code :
int *aptrx = malloc(sizeof(int));
int *aptrx = &x;
printf("aptrx is %p\n", aptrx);

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Basic pointers and qsorting

By : Ashok Patel
Date : March 29 2020, 07:55 AM
seems to work fine You modify begin in your loop, so you lost that pointer and you end up calling qsort with the wrong pointer. How about something saner like this:
code :
int isort(int * const begin, int * const end)
    qsort(begin, end - begin, sizeof(int), int_cmp);
    return end - begin;

Basic Pointers in C?

By : Yin
Date : March 29 2020, 07:55 AM
This might help you I have three difference examples mention below. I don't understand why ex1 has same output for ex2 and differ output for ex3, also why ex2 is not the same as ex3 where I just make a creation in another line!! , In example 3, you first declare a pointer:
code :
int *y;
int *y;
y = &x;

Can't figure out pointers in C++! Need info about basic strings and pointers

By : Cupoto
Date : March 29 2020, 07:55 AM
help you fix your problem I'm guessing this is the first time you've come across pointers. If you don't quite understand them, I'd highly recommend going and learning about them as they are pretty critical to C/C++ (among other languages).
For the benefit of this question, though, I'll give a very rough definition. A pointer "points" to a specific memory location. Its "type" is used to define how much memory it expects to use at that point. That is, a char* pointer will only expect to handle a char's worth of data, and will only reserve that much memory. A long* will reserve and handle a long's worth of memory (significantly larger, how much more depends on the system, but that's another subject).
code :
char *adr = strchr(str, ' '); //value might be NULL

Basic C++ String Pointers

By : zongfa chen
Date : March 29 2020, 07:55 AM
will be helpful for those in need *p is not "the variable". p is the variable and it is a pointer. C and C++ have the odd looking declaration syntax in which you declare a variable with the same kind of syntax used to access the variable.
code :
char *p;
char *p = "Hello";
char *p = "Hello";
p = "Bye";

C pointers - the very basic

By : Arnab Kundu
Date : March 29 2020, 07:55 AM
it fixes the issue Because you are assigning an arbitrary address to the pointer, and you have no guarantee that it is valid or if it's writeable or readable by your program.
A pointer needs to point to valid memory in order to dereference it, to make a pointer point to valid memory you can declare a variable in the function and point to it's address in the stack like this
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