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Compare 2 big string lists


By : nikhildewne
Date : September 13 2020, 08:00 AM
wish of those help I'm assuming that you only want to match on the specific words in your text list: that is, if text contains "dogs", and words contains "dog", then that shouldn't be a match.
Note that this is different to what your code currently does.
code :
var textWords = new HashSet<string>(StringComparer.OrdinalIgnoreCase);
foreach (var line in text)
{
    var lineWords = line.Split(' ');
    textWords.UnionWith(lineWords);
}

if (textWords.Overlaps(words))
{
    // One thing
}
else
{
    // Another
}
if (line.IndexOf(word, StringComparison.OrdinalIgnoreCase) >= 0)


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Best way to compare two large string lists, using C# and LINQ?


By : user1683166
Date : March 29 2020, 07:55 AM
This might help you I have a large list (~ 110,000 strings), which I need to compare to a similar sized list. , So you have two lists like so:
code :
List<string> listA;
List<string> listB;
List<string> except = listA.Except(listB).ToList();
List<string> except = listA.Except(listB, StringComparer.OrdinalIgnoreCase).ToList();

How does Python 2 compare string and int? Why do lists compare as greater than numbers, and tuples greater than lists?


By : macguyver13
Date : March 29 2020, 07:55 AM
This might help you From the python 2 manual:
code :
>>> 5 < 'foo'
True
>>> 5 < (1, 2)
True
>>> 5 < {}
True
>>> 5 < [1, 2]
True
>>> [1, 2] > 'foo'   # 'list' < 'str' 
False
>>> (1, 2) > 'foo'   # 'tuple' > 'str'
True

>>> class Foo(object): pass
>>> class Bar(object): pass
>>> Bar() < Foo()
True
>>> class Foo: pass           # old-style
>>> class Bar(object): pass   # new-style
>>> Bar() < Foo()
False
>>> '10' > 5
Traceback (most recent call last):
  File "<pyshell#0>", line 1, in <module>
    '10' > 5
TypeError: unorderable types: str() > int()

Compare two string lists with each other Python


By : Andrei Terentiev
Date : March 29 2020, 07:55 AM
hope this fix your issue You can use str.startswith which can take a tuple of items as argument. Left strip each item in the first list and check if the item startswith any of the strings in the second list:
code :
t = tuple(my_list2)
lst = [x for x in my_list1 if x.lstrip().startswith(t)]
print lst
# ['     15,         -28.,         -30.\n']

Scala compare two lists and build string


By : Remon
Date : March 29 2020, 07:55 AM
I wish this helpful for you The use of null is generally discouraged in Scala, that is why I can suggest making this mapping to List[Option[String]]. This will allow to benefit securely from functional calls on the transformed data.
So, supposing you have these initial values:
code :
private val columns =
  List("col1", "col2", "col3", "col4", "col5", "col6", "col7", "col8", "col9", "col10", "col11", "col12", "col13")

private val input = List(
  Map("col2" -> "dummy string", "col7" -> "2016-01-01", "col11" -> "2011-01-01"),
  Map("col2" -> "dummy string", "col7" -> "2018-01-01", "col11" -> "2018-01-01"),
  Map("col2" -> "dummy string", "col7" -> "2018-04-01", "col11" -> "2018-04-01"),
  Map("col2" -> "dummy string", "col7" -> "2016-01-01", "col11" -> "2016-01-01")
)
val rows = input.map(originalMap =>
  columns.map(column => originalMap.get(column))
)
List(None, Some(dummy string), None, None, None, None, Some(2016-01-01), None, None, None, Some(2011-01-01), None, None)
val resultWithNulls = rows.map(row => row.map(_.getOrElse(null)))
List(null, "dummy string", null, null, null, null, "2016-01-01", null, null, null, "2011-01-01", null, null)
val resultAsCsvString = rows.map(row => row.map(_.getOrElse("")).mkString(","))
// List(
//  ",dummy string,,,,,2016-01-01,,,,2011-01-01,,",
//  ",dummy string,,,,,2018-01-01,,,,2018-01-01,,",  ...
// )

Compare two lists : One contain object, one other contain string


By : techbysample.com
Date : March 29 2020, 07:55 AM
help you fix your problem I'm trying to compare two list to add (in an other list) my lights that I want. I want to get light object by string name , You could use Join for the purpose
code :
var selectedList = lights.Join(lightsWanted,x=>x.Name,y=>y,(x,y)=>x);
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