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Calculating n! and x^n and proceeding the calculation

By : Tichafara A Ndoro
Date : September 13 2020, 09:00 AM
fixed the issue. Will look into that further Write a C program to calculate (x^n)/(n!) where x is a floating point number and n is an integer greater than or equal to zero. , In your question I have recognize 3 problems.
code :

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What is the proper way of calculating this flow calculation in Objective C?

By : Psigen
Date : March 29 2020, 07:55 AM
may help you . It's a little hard to see what the problem you're having is. Is it the syntax needed to do square roots and powers?
Square root: sqrtf(float)
code :
// sqrt((1-((p2+0.1)/(p1+0.1))-b) / (1-b))^2
float part1 = (p2 + 0.1) / (p1 + 0.1);
float part2 = (1 - part1 - b) / (1 - b);
float part3 = sqrtf(part2);
float result = part3 * part3;

javascript calculation not calculating

By : goPie
Date : March 29 2020, 07:55 AM
hop of those help? if "now" and "startDate" are objects, then every time you call

PHP Calculation from database not calculating correctly.

By : StudentUC
Date : March 29 2020, 07:55 AM
I wish did fix the issue. Rookie Error, i had updated the database twice in one day which conflicted the results somehow, changed one of the dates in the database and this solved the problem

Why is a calculating for every row faster than checking if calculation has been done?

By : JustAnotherDev
Date : March 29 2020, 07:55 AM
hope this fix your issue There are just a lot to optimize. Try learning data manipulation packages like dplyr, data.table.
min1 can be calculated using the technique from here
code :
dfs <- split(df$ID, df$timeslot)
df$min1 <- unlist(mapply(`%in%`, dfs,  lag(dfs)))
df1 <- df %>% 
  group_by(timeslot, ID) %>% 
  summarise(min1 = all(min1), s = sum(variable1^5), n = n()) %>% 
  group_by(ID) %>% 
  mutate(s1 = s + lag(s), n1 = n + lag(n), lp5 = ifelse(min1, abs((s1/n1)^(1/5)), NA)) 
lp5 <- df1$lp5
dt1 <- df[, .(min1 = all(min1), s = sum(variable1^5), n = .N), by=.(timeslot, ID)]
dt1[, `:=`(s1 = s + shift(s), n1 = n + shift(n)), by=ID]
dt1[min1==TRUE, lp5 := abs((s1/n1)^(1/5)), by=ID]
lp5 <- dt1$lp5

Calculation is not calculating correctly

By : Giuseppe Valentino B
Date : March 29 2020, 07:55 AM
it fixes the issue This operation: a + t + b has the following elements:
a is a number t is a string (its value is -) b is a number
code :
if (t == '+')
    r = a + b;
    r = a - b;
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