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How can I run through all the characters of a string and check if they're all numbers in C?


By : Omar
Date : September 14 2020, 02:00 AM
this will help For starters the function read shall accept its argument by reference like
code :
void read(struct id *s);
scanf("%s", s.id_num);
void read( struct id *s )
{
    //...
    fgets( s->id_num, sizeof( s->id_num ), stdin );
    s->id_num[strcspn( s->id_num, "\n" )] = '\0';
int isNumber( const char p[] ) 
{
    const char *s = p;
    while ( isdigit( ( unsigned char )*s ) ) ++s;

    return  p[0] != '\0' && *s == '\0';
}
#include <stdio.h>
#include <ctype.h>

int isNumber( const char p[] ) 
{
    const char *s = p;
    while ( isdigit( ( unsigned char )*s ) ) ++s;

    return  p[0] != '\0' && *s == '\0';
}

int main(void) 
{
    printf( "Is a number - %s\n", isNumber( "" ) ? "true" : "false"  );
    printf( "Is a number - %s\n", isNumber( "A" ) ? "true" : "false"  );
    printf( "Is a number - %s\n", isNumber( "12A" ) ? "true" : "false"  );
    printf( "Is a number - %s\n", isNumber( "123" ) ? "true" : "false"  );

    return 0;
}
Is a number - false
Is a number - false
Is a number - false
Is a number - true


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Check if string contains no characters except numbers?


By : user3078456
Date : March 29 2020, 07:55 AM
it helps some times You can use is_int
code :
$time = explode(":",$time);

if ($time['0'] > 12 || $time['0'] < 1 || !is_int($time[0]))
{
    //error: not valid hour
    echo("error: time val hour is bad");
}

Check if a string has no characters or numbers at all


By : ufser
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , In php, how can I check if a string has no characters at all.
code :
$fetch = false;

#$strFromSearchBox = 'Why-you-foo-bar-I-ought-to-tar-you';
$strFromSearchBox = 'foo-bar-tar';

if(strlen($strFromSearchBox) >=2)
{
    $newString = str_replace($theseWords,'',$strFromSearchBox);
    $newString = str_replace('-',' ',$newString);
    $newString=trim($newString);  //This will make the string 0 length if all are spaces
    if(strlen($newString)>=2)
    {   
        $fetch = true;
        echo $newString;
    }
}


if($fetch){echo 'True';}else{echo 'False';}

Python - Check if the last characters in a string are numbers


By : Abhi
Date : March 29 2020, 07:55 AM
I wish this helpful for you Basically I want to know how I would do this.
code :
import re
m = re.search(r'\d+$', string)
# if the string ends in digits m will be a Match object, or None otherwise.
if m is not None:
    print m.group()

Check string for numbers and characters in Oracle 11G


By : Karan Luthra
Date : March 29 2020, 07:55 AM
I wish did fix the issue. ok I'm not exactly clear on what you are doing however maybe the following might help. creating a table from data
code :
create table mytable as select 'NL 4633 4809 KTU' txt from dual;
SELECT  REGEXP_SUBSTR (txt, '[^ ]+', 1, 1)    AS part_1
,       REGEXP_SUBSTR (txt, '[^ ]+', 1, 2)    AS part_2
,       REGEXP_SUBSTR (txt, '[^ ]+', 1, 3)    AS part_3
,       REGEXP_SUBSTR (txt, '[^ ]+', 1, 4)    AS part_4
FROM    mytable;
part1 part2 part3 part4
NL 4633 4809 KTU
select REGEXP_SUBSTR (txt, '[^ ]+', 1, level) val from mytable connect by level <= regexp_count(txt,' ') + 1;
NL
4633
4809
KTU

Check if string contains ONLY NUMBERS or ONLY CHARACTERS (R)


By : Z.Vula
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further I have these three strings: , you need to persist your regex
code :
all_num <- "123"
all_letters <- "abc"
mixed <- "123abc"


grepl("^[A-Za-z]+$", all_num, perl = T) #will be false
grepl("^[A-Za-z]+$", all_letters, perl = T) #will be true
grepl("^[A-Za-z]+$", mixed, perl=T) #will be false
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