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Why does this macro expression in C behave unexpectedly?

By : user6096639
Date : September 14 2020, 11:00 AM
may help you . The problem is that the definition of your macro doesn't have any parentheses in it - and macros aren't 'called', like functions are - they just cause text to be replaced.
So, in your code, the line:
code :
int p=36/square(6);
int p=36/6*6;
int p = (36/6) * 6;
#define square(x) ((x)*(x))

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Why does this use of wxPython's EVT_KILL_FOCUS behave unexpectedly?

By : Heggman
Date : March 29 2020, 07:55 AM
I wish this helpful for you As explained in wxEvent::Skip() documentation, you should almost invariably call it for non-command events as you don't want to prevent the default handling from taking place.

why ng-model behave unexpectedly in angularjs?

By : Chochukka
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , This has to do with how scope inheritance works. For a more comprehensive answer on nuances of scope inheritance, read this SO answer.
First, you have to recognize that ng-controller directive creates a child scope that prototypically inherits from the parent, and so you have nested scopes here of the following hierarchy (the numbers are $ids of each scope)
code :
 /  \
#5  #3
.controller("maincontroller", function($scope){
   $scope.data = {};

Why do my program behave unexpectedly when I use sigaction?

By : Nikolay Ivanitskiy
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , Your program exits with EINTR (interrupted system call) from getline function (getline is interrupted by signal handler).
Check this: How to handle EINTR (interrupted System Call)

JavaScript closures behave unexpectedly

By : Vivek
Date : March 29 2020, 07:55 AM
will help you This is the nature of using let to declare a variable in javascript — it's scoped to the (implied here) for loop block, which means each iteration gets a newly scoped name that is captured in each closure. The closures aren't all using the same name like they would be in some other languages, or in JS when using var to declare a variable.
To get your expected behavior, use var:
code :
const arr = [];
for (var i = 0; i < 10; i++)
    arr.push(() => i * i);

arr.forEach(f => console.log(f()));

Why does += behave unexpectedly on lists?

By : user3849859
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , The general answer is that += tries to call the __iadd__ special method, and if that isn't available it tries to use __add__ instead. So the issue is with the difference between these special methods.
The __iadd__ special method is for an in-place addition, that is it mutates the object that it acts on. The __add__ special method returns a new object and is also used for the standard + operator.
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