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Difference between a VOID function with a string argument VS a function with a string argument that returns a char array


By : Isna Ijal
Date : September 14 2020, 01:00 PM
Hope this helps Returning the original pointer provides the ability to nest function calls more readily:
code :
printf("%s\n", my_strcat(name, lastName));
my_strcat(name, lastName);
printf("%s\n", name);
for (char *letter = appending; *letter != '\0'; letter++)
    word[len++] = *letter;
for (char *letter = appending; *letter != '\0'; letter++)
{
    word[len++] = *letter;
}
word[len] = '\0';
while (word[len] = *appending)
{
   appending++;
   len++;
}


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Declaring an array of function pointer that takes void as argument and returns an array of pointers to integers


By : Hiroko Inobe
Date : March 29 2020, 07:55 AM
will help you Let's see... a function pointer p that takes void as an argument can be declared like so:
code :
void (*p)(void);
 int** (*p)(void);
int* (*(*p)(void))[100];
int* (*(*ptrs[7])(void))[100];
int* (*(*ptrs[7])())[100];

`Cannot convert 'char(*)[50]' to 'char**' for argument '1' to 'void prac(char**)'` when passing a 2D array to a function


By : user3734559
Date : March 29 2020, 07:55 AM
Any of those help The name of a two-dimensional arrays gets converted ("decay") to a pointer to the address of the first row of the array. So use
code :
void prac(char b[][50])
void prac(char (*b)[50])
void prac(char **b)

Passing each argument of a variadic function template into a function that returns void


By : Arpana G
Date : March 29 2020, 07:55 AM
With these it helps This syntax means, that temp will be std::initializer_list filled with zeros, due comma operator rules (all expressions will be evaluated, but only last will be used, so, function printInt will be called for each argument and 0 will be putted to initializer list for each argument).
N4296 5.19/1
code :
{(printInt(args), void(), 0)...};
{((void)printInt(args), 0)...};
{0, ((void)printInt(args), 0)...};

What is the difference in using variable as function argument and in using directly string as function argument?


By : user3647843
Date : March 29 2020, 07:55 AM
I hope this helps . As per your description, it seems that the prototype of your function
code :
func(char* str);
func(char str[]);
str = "Any String";
func(str.toCharArray());

Passing a function which returns void but has integer arguments to another function as an ARGUMENT itself


By : Alharith
Date : March 29 2020, 07:55 AM
With these it helps g_slider_position is accessible to your function -- you can't pass it. You should use the code you have (from your friend), but the int passed is the id of the trackbar.
Should be this:
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