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Can't sort array containing int

By : Albert Hung
Date : September 14 2020, 04:00 PM
may help you . Based on your recent update, it seems asr is an array with properties you've added. That's not generally a good idea unless you know what you're doing, and sort() won't touch those properties.
Instead, I would use a normal object, with the caveat that objects in JavaScript aren't really meant to contain an ordered collection of values. With that caveat out of the way, this is how I'd store the data, and how I'd sort the keys:
code :
const asr = {by: 3, ds: 14, de: 2, vi: 1, sr: 2}

    ([ak, av], [bk, bv]) => av > bv ? 1 : -1
const asr = [{vi: 1}, {sr: 2}, {by: 3}, {ds: 14}, {de: 2}]

const asr = [{vi: 1}, {sr: 2}, {by: 3}, {ds: 14}, {de: 2}]

  (a, b) => Object.values(a)[0] > Object.values(b)[0] ? 1 : -1
const asr = [{vi: 1}, {sr: 2}, {by: 3}, {ds: 14}, {de: 2}]

  (a, b) => Object.keys(a)[0] > Object.keys(b)[0] ? 1 : -1

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Choosing minimum length k of array for merge sort where use of insertion sort to sort the subarrays is more optimal than

By : Elena Urquiola
Date : March 29 2020, 07:55 AM
like below fixes the issue Well, this is a mathematical minimization problem, and to solve it, we need some basic calculus.
We need to find the value of k for which d[n*k + n*lg(n/k)] / dk == 0.
code :
d[n*k + n*lg(n/k)] / dk = d[n*k + nlg(n) - nlg(k)] / dk
= n + 0 - n*1/k = n - n/k 
n - n/k = 0 => n = n/k => 1/k = 1 => k = 1

sort 2d String array in java -sort index element inside my array

By : Alina Belokon
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further Hi i need to sort array two Dimension in java but i need the sorting to be by index inside my array my array is , Here is the solution with Comparator:
code :
public class SortTest {
    public static void main(String[] args) {
        String arr[][]={  {"joun","1525565","10"},
                {"FATEH","1525534","20"}   };

        Arrays.sort(arr, new Comparator<String[]>() {
            public int compare(String[] o1, String[] o2) {
                return Integer.parseInt(o2[2]) - Integer.parseInt(o1[2]);

        for (String[] item : arr) {

Sort multi-dimensional array, append text and then continue to sort array by number value in javascript

By : perro123
Date : March 29 2020, 07:55 AM
With these it helps When you add pixel, you have strings and not numbers. So you need to parse out the number
code :
convertToArray: function(e){
   var xVal = (Math.floor(e.offsetX / s.pixSize) * s.pixSize) + "px";
   var yVal = (Math.floor(e.offsetY / s.pixSize) * s.pixSize) + "px";
   s.storeValues.push([xVal, yVal]);
   var compare = function(a, b) { return parseFloat(a[0]) - parseFloat(b[0]); };

How to prompt user to input a number to get size of array. Then sort array using bubble sort method

By : syam ash
Date : March 29 2020, 07:55 AM
wish helps you Haven't practiced Java in a long while so any help would be appreciated. , You could do as follows:
code :
import java.util.Arrays;
import java.util.Scanner;
import java.util.Random;
public class BubbleTest {

    public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);
        System.out.println("Please enter a number to create array."+"\n");
        int z = scan.nextInt();
        int [] array = new int[z];
        // Randomly generating array elements

        for(int i =0; i<z; i++){
            array[i]=new Random().nextInt();
      //  z = scan.nextInt();

        //Bubble Sort
        for(int i = array.length-1; i>=0; i--)
            for(int j=0; j<i; j++)
                if(array[j] > array[j+1])
                    int temp = array[j];
                    array[j] = array[j+1];
                    array[j+1] = temp;



Force chrome to do use merge sort or quick sort for array#sort

By : o_O
Date : March 29 2020, 07:55 AM
wish helps you Stable sort in Array#sort? No, you can't specify algorithm to use (and standard doesn't say anything about it). So you can either write your own sort function or extend the key:
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