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How to properly destructure assignment with dynamic key? (react/destructuring-assignment)


By : Dom Parise
Date : September 14 2020, 06:00 PM
will help you so, I was able to get there with the comments.
At the end of the day, I realized I just needed 'edited' to be an object containing the destructured object.
code :
 _onChange = (e, key) => {
    const { [key]: { ...edited } } = this.state;
    edited[e.name] = e.value;
    this.setState({
      [key]: edited,
    });
  };
 _onChange = (e, key) => {
    const { [key]: current } = this.state;
    this.setState({
      [key]: { ...current, [e.name]: e.value },
    });
  };


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ES6 destructuring, dynamic assignment


By : user3799166
Date : March 29 2020, 07:55 AM
wish helps you , You need parens around the assignment:
code :
let text, value;
if (typeof f == 'string') {
    text = value = f;
} else {
    ({                // ( at start
        text, value
    } = f);           // ) at end
}
let text, value;
if (typeof f == 'string') {
    text = value = f;
} else {
    +{                 // <== Doesn't work like it does with IIFEs
        text, value
    } = f;
}

Destructuring assignment via TypeScript in React


By : Dan Flyer
Date : March 29 2020, 07:55 AM
like below fixes the issue How should I do something like , You have to define a type for props:
code :
interface Props {
    x: string;
    y: number;
    z: string;
}

class App extends React.Component<Props, {}> {
    render() {
      const { x, y, z} = this.props;
      return (...)
    }
}

Must use destructuring props assignment (react/destructuring-assignment)


By : sup
Date : March 29 2020, 07:55 AM
around this issue I've applied eslint airbnb standard to my code, so now this code:
code :
handleSubmit = (event) => {
    event.preventDefault();

    const {onSearch} = this.props
    const {value} = this.query
    onSearch(value)

    event.target.blur();
}

I've been given an assignment on destructuring, can someone help me understand how to destructure object { } nested with


By : user3174471
Date : March 29 2020, 07:55 AM
may help you . Object/Array destructuring is simply a syntax that allows for property/index access of an Object or an Array.
Example of Object destructuring to access a property:
code :
var user = {
  name: "fred"
};

var { userName } = user; 
var users = [
  {
    name: "fred"
  },
  {
    name: "joe"
  }
];

var [userOne] = users;
// ^-- userOne now holds the object at index `users[0]`
var userList = {
  people: [
    {
      firstName: "Fred",
      lastName: "Smith",
      dateOfBirth: 1980,
      spokenLanguages:
      {
        native: "English",
        fluent: "Spanish",
        intermediate: "Chinese"
      }
    },
    {
      firstName: "Monica",
      lastName: "Taylor",
      dateOfBirth: 1975,
      spokenLanguages:
      {
        native: "Spanish",
        fluent: "English",
        intermediate: "French"
      }
    }
  ]
};

// Assign the value of `userList.people (Array)` to the variable `people`
var { people } = userList;

// Iterate each 'person' in the `people` Array
for (var i = 0; i < people.length; i++) {

  var person = people[i];

  /**
   * Assign the property values of the temporary variable `person` to
   * the variables `firstName`, `lastName`, `dateOfBirth`, and `spokenLanguages`.
   */
  var { firstName, lastName, dateOfBirth, spokenLanguages } = person;

  /**
   * Assign the property values of the variable `spokenLanguages` to the variables
   * `native`, `fluent`, and `intermediate`. 
   */
  var { native, fluent, intermediate } = spokenLanguages;

  console.log(firstName, lastName, dateOfBirth, native, fluent, intermediate);
}

Is destructuring assignment guaranteed to be parallel assignment in Swift?


By : Sommy
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further Tuples are value types, and once constructed they are independent of the values that are part of them.
code :
var a = 2
var b = 3
var t1 = (a, b)
print(t1) // (2, 3)
a = 4
print(t1) // (2, 3)
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