 Tags IOS SQL HTML C RUBY-ON-RAILS MYSQL ASP.NET DEVELOPMENT RUBY .NET LINUX SQL-SERVER REGEX WINDOWS ALGORITHM ECLIPSE VISUAL-STUDIO STRING SVN PERFORMANCE APACHE-FLEX UNIT-TESTING SECURITY LINQ UNIX MATH EMAIL OOP LANGUAGE-AGNOSTIC VB6 # How to switch every two elements in a vector in R?

By : user6096521
Date : September 14 2020, 08:00 PM
around this issue For example I have a vector as follows: , Another solution code :
``````x[1:length(x) + c(1, -1)]
``````

## Syntax (and/or functions) for applying an op over elements of one vector, using as arg elements of a 2nd vector

By : Romeu Dias
Date : March 29 2020, 07:55 AM
hope this fix your issue I am trying to find the right expression for creating a vector result by applying an operation over an vector, using, in a vectorised way, elements of a 2nd vector. The use case is that I have a vector of raw values, and a vector of breakpoints. What I want is an expression that will give me the result of applying a sum of a logical operation on the breakpoints with respect to the values in the values vector. In other words: , You can do it in three steps:
code :
`````` as.data.frame(t(sapply(breaksfoo,
function(x) list(breaks = x, nmatching = sum(x > rawfoo)))))
``````
``````  breaks nmatching
1     10         2
2     50         5
3     80         6
``````

## loop to remove repeated elements of a vector and add corresponding elements of another vector

By : Sam Peter
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , I would prefer using built in functions, but assuming you have to stick to your own approach, you can try this:
code :
``````a=[5,6,8,9,6,7,9,10,8,9,11,12];
b=[1,7,1,-1,3,21,3,-3,-4,-28,-4,4];

n = numel(a);
remove = zeros(1,n);

temp = a;
for ii = 1:n
for jj = ii+1:n
if temp(ii) == temp(jj)
temp(ii) = NaN;
remove(ii) = ii;
b(jj) = b(jj) + b(ii);

end
end
end

a(remove(remove>0)) = []
b(remove(remove>0)) = []

a =
5     6     7    10     8     9    11    12
b =
1    10    21    -3    -3   -26    -4     4
``````

## How to replace specific elements of a vector with elements of a string vector?

By : kevin jenkins
Date : March 29 2020, 07:55 AM
Any of those help As you have already shown a lot of effort I will try to clear some things up for you. The replacement of 1 to 5 with 65 to 70 is due to the ASCII table which represents all characters with integers. As you have an integer array MATLAB will convert the characters with its numerical ASCII value. You can invert this with char(65:70) = ABCDEF;
Also you can index the position of grades multiple times. char_grades =letters(grades) will do the trick. Or to do it in a convoluted way.
code :
``````g = @(x) letters(x);
``````

## Elements of character vector within switch statement

By : Carlos Ricardo Ortiz
Date : March 29 2020, 07:55 AM
it fixes the issue b=1 is literally trying to assign 1 to the first element of b I think, which is not going to work in this context. You want a named object passed as an argument to switch(), like you have in example 3.
code :
``````switch(b, "1"=1, "2"=2, "3"=3)
# 2
``````
``````do.call(switch, c(b, setNames(list(1,2,3), b[1:3])) )
# 2
``````
``````c(b, setNames(list(1,2,3), b[1:3]))
#[]
# "2"
#
#\$`1`
# 1
#
#\$`2`
# 2
#
#\$`3`
# 3
``````

## Counting the number of elements in vector x which equal any vector element in vector y

By : user3427344
Date : March 29 2020, 07:55 AM
wish help you to fix your issue I need to count the number of elements in vector x which equal any vector element in vector y. , Try length-which-in:
code :
``````length(which(x %in% y))
`````` 