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How to forward declare enum class as inner class of a templated class?

By : Anirudh
Date : September 14 2020, 10:00 PM
Hope that helps I'm abstracting the interrupt vector table on multiple microcontrollers. I am using template classes in the form of (InterruptVectorTable.hpp(definition, included in implementation)) , First of all, this is not how you introduce a new template class:
code :
// Wrong!
InterruptVectorTable<class Device, class ResultType>
    // ...
template<class Device, class ResultType>
class InterruptVectorTable
    // ...
class InterruptVectorTable<DeviceAtMega328p, uint8_t>
    enum class IRQType : uint8_t
        //RESET_IRQn = 0,               // Not available.
        INT0_IRQn = 1,
        INT1_IRQn = 2,
        PCINT0_IRQn = 3,
        PCINT1_IRQn = 4,
        PCINT2_IRQn = 5,
        WDT_IRQn = 6, 

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How do I forward declare a class derived from a forward declared template base class?

By : jell22
Date : March 29 2020, 07:55 AM
it helps some times I am trying to forward declare a class that is derived from a template class that must also be forward declared. , Just forward declare the class name:
code :
class Derived;

Is it possible to forward declare a enum class to be used in a derived class?

By : V Share Rose
Date : March 29 2020, 07:55 AM
wish of those help That's declaring that there's an enum called LineType inside Parser or: Parser::LineType .
In the derived class you have an enum called LineType, and its full 'name' will be: GUIParser::LineType.

Using a class as a template parameter for a templated class with forward declaration

By : Modassarrahman Rahma
Date : March 29 2020, 07:55 AM
this will help Bar requires the full Foo definition because it contains a data member of type Foo. You could not forward declare in this case. In this respect, Bar is the equivalent of
code :
class BarFoo 
    Foo baz;

How to forward declare templated type that should belong to a class?

By : Brian Folk Caldwell
Date : March 29 2020, 07:55 AM
wish of those help You can't forward declare a nested typedef since at the point of the forward declaration B would be an incomplete type. You can however solve your problem like below:
code :
class B;

class A {
  std::shared_ptr<B> _b;
  typedef std::shared_ptr<A> Ref;

class B {
  A::Ref _a;
  typedef std::shared_ptr<B> Ref;

How to Forward Declare a Class that Relies on a Variant Definition, Which In Turn Relies on a Templated Class?

By : mcmatt90
Date : March 29 2020, 07:55 AM
This might help you I don't think you can.
The variant's alternatives must all be complete types, and your Fum stores a T as a member.
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