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Count amount of times an id appears in column store in new column


By : Lion Orange
Date : September 15 2020, 04:00 AM
fixed the issue. Will look into that further I have a table that looks as following: , Most of DBMS's supports window function, so you can use :
code :
SELECT t.ID, COUNT(*) OVER (PARTITION BY t.id) AS Count 
FROM table t;
SELECT t.id, (SELECT COUNT(*) FROM table t1 WHERE t1.id = t.id) AS Count 
FROM table t


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How to count the number of times a column name appears AND that column has a nonblank cell


By : anilkumar reddy
Date : March 29 2020, 07:55 AM
it should still fix some issue You can't use an OR function in COUNTIFS quite like that, try this approach....
=SUM(COUNTIFS(Attendance!$C$2:$BS$2,'Players vs. Teams'!C$2,Attendance!$C3:$BS3,{"W","L","T"}))

R: Cumulatively count number of times column value appears in other column


By : SH LEE
Date : March 29 2020, 07:55 AM
this one helps. Have used and edited Backlin's answer to get what I want, code is as follows
code :
df$count<- NA 

split(df, df$var) <- lapply(split(df, df$var), function(x){
    x$count<- sapply(1:nrow(x), function(i) sum(x$id2[i] == x$id1[1:i]))
    x
})

Python Pandas: How can I count the number of times a value appears in a column based upon another column?


By : Dev Rahul
Date : March 29 2020, 07:55 AM
Hope that helps I believe you need groupby with size:
code :
df1 = df.groupby(['crime type', 'council']).size().reset_index(name='Count')
df = pd.DataFrame({'crime type':['Anti-social behaviour','Anti-social behaviour',
                                 'Burglary','Burglary'],
                   'council':['Fermanagh and omagh','Belfast','Belfast','Belfast']})


df1 = df.groupby(['council', 'crime type']).size().unstack(fill_value=0)
print (df1)
crime type           Anti-social behaviour  Burglary
council                                             
Belfast                                  1         2
Fermanagh and omagh                      1         0

df1.plot.bar()

Count times a value of a column appears and add a column to the dataframe with it


By : user2077090
Date : March 29 2020, 07:55 AM
it should still fix some issue I have a dataframe with 4 columns, one of them being people's names and another one activity they practiced. I want that in front of each row appears the number of times that combination appears. All the ways i found of counting change the dataframe or reduce the size of the data frame, apearing each combination only one time. I would like the dataframe to stay the same just with one more column with the number of times that combination exists. Does anyone know a way? , groupby + size
Assuming your grouper columns are 0 and 2:
code :
df['combination_count'] = df.groupby([0, 2])[1].transform('size')
cols = df.columns.tolist()
cols.insert(0, cols.pop(cols.index('combination_count')))
df = df.reindex(columns=cols)

Order a dataframe primarily by the count of times a value appears in a column and secondarily by a second column


By : user2959513
Date : March 29 2020, 07:55 AM
should help you out I have the dataframe below which I would like to order primarily numerically by the count of times a value appears in the first column (bigger values first) and secondarily alphabetically(A-Z) based on the second column. , As suggested by @thelatemail, you can do this in base R using:
code :
n1[order(-table(n1$Name)[n1$Name], n1$Surname), ]
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