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How to add the two or more numbers in to string in java?

By : youcz94
Date : September 15 2020, 08:00 AM
I hope this helps . It's String concatenation. As soon as there is a String added, all the next elements will be added to the String, not as an int.
code :
String a = 10 + 5 + " result";
10 + 5 + " result";
15 + " result";
"15 result";

String a = 10 + " result " + 5 + 2;
"10 result " + 5 + 2;
"10 result 5" + 2;
"10 result 52"; 
String a = 10 + " result " + (5 + 2);
String val = 5 + 5;

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Testing for specific numbers order for character and numbers in a string in java

By : Geraldo Silva
Date : March 29 2020, 07:55 AM
hop of those help? Right what I was trying to do is validate some input so that the input must start with 2 letters and followed by 3 digits, but I can't find a way of testing a string for this , Sounds like you want a regular expression...
code :
// Do this once and cache it...
Pattern pattern = Pattern.compile("\\p{Alpha}{2}\\d{3}");

// Then test it:
boolean test = pattern.matcher(str).lookingAt();

String Manipulation: Taking numbers out of a string in java?

By : lwl
Date : March 29 2020, 07:55 AM
wish help you to fix your issue I want to be able to extract certain things from strings such as numbers, what is the most efficient way to perform this action in terms of both speed and accuracy? , You can do that for each line :
code :
String[] tokens = line.split(" ");
String timeString = tokens[tokens.length-2];
float time = Float.parseFloat(timeString);

Java, replace string numbers with blankstring and remove everything after the numbers

By : fedkanaut
Date : March 29 2020, 07:55 AM
To fix the issue you can do I have strings like: , With a regex, it's pretty simple:
code :
public class Test {

    public static String replaceAll(String string) {
        return string.replaceAll("\\d+.*", "");

    public static void main(String[] args) {
        System.out.println(replaceAll("Alian 12WE"));

Java program that converts binary numbers to decimal numbers. The input is a string of zeros and ones

By : user3048648
Date : March 29 2020, 07:55 AM
hop of those help? Do this only if your decimal value is at most 2147483647 or the maximum value an int can be in Java. If you don't know, just check the length of your string. If it's less than or equal to 32 i.e. 4 bytes, then you can use parseInt.:
code :
int decimalValue = Integer.parseInt(s, 2);
 String s = "1001010101011010111001011101010101010101";
 long result = 0;
 for(int i = 0; i < s.length(); i++){
    result = (long) (result + (s.charAt(i)-'0' )* Math.pow(2, s.length()-i-1));

Capitalize words in a string but skip numbers and superfluous spaces or symbols in the string in java

By : user3419760
Date : March 29 2020, 07:55 AM
Any of those help Edit: It looks like @Andy Turner gave you the answer, but here is the code that he was hinting at.
code :
public static String capsFirst(String str) 
        String[] words = str.split(" ");

        StringBuilder ret = new StringBuilder();

        for(int i = 0; i < words.length; i++) 
          if (words[i].length() == 0){
            ret.append(' ');

          if (Character.isLetter(words[i].charAt(0))){

            if(i < words.length - 1) 
                ret.append(' ');

        return ret.toString();
public class Capitalize

    public static void main(String [] arg)

        String x = "london   england 2015";

        String y = capsFirst(x);


    public static String capsFirst(String str) 
        boolean betweenWords = false;
        char[] chars = str.toCharArray();

        for(int i = 0; i < chars.length; i++) 
          if (chars[i] == ' '){
            betweenWords = true;

          if (betweenWords || i == 0){
            if (Character.isLetter(chars[i])){
              chars[i] = Character.toUpperCase(chars[i]);

            betweenWords = false;


        return new String(chars);
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