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SQL distinct column with sum of corresponding value


By : qcambrel
Date : September 15 2020, 08:00 AM
I hope this helps you . You can use the following, using GROUP BY with SUM:
code :
SELECT brand, SUM(units) AS Units
FROM table_name
GROUP BY brand


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MySQL select all distinct values from column a for each distinct column b, where count distinct a >1


By : neoWP
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , OK, I think you mean this...http://sqlfiddle.com/#!3/b6100/6
Given
code :
create table loginattempts  
(
  login_key int,
  mac varchar(12) null,
  username varchar(12) null
)

insert into loginattempts values (1, 111, 'peter')
insert into loginattempts values (2, 111, 'bob')
insert into loginattempts values (3, 222, 'geoff')
insert into loginattempts values (4, 222, 'lisa')
insert into loginattempts values (1, 333, 'peter')
   select mac, username
   from loginattempts
   where
    mac in
    (
      select mac
      from loginattempts
      group by mac
      having count(*) > 1
     )
MAC USERNAME
111 peter
111 bob
222 geoff
222 lisa

Mysql query to select a distinct column and the count of a value in another column where column like distinct coumn?


By : ganesh kumar
Date : March 29 2020, 07:55 AM
This might help you You can use an aggregate function with a CASE expression to convert the rows into columns:
code :
select week,
  sum(case when result = 'good' then 1 else 0 end) GoodResult,
  sum(case when result = 'bad' then 1 else 0 end) BadResult
from yt
group by week;

SQL return a Distinct column and the first date of the distinct column


By : BlastEye
Date : March 29 2020, 07:55 AM
hop of those help? I have a database that contains multiple url and a date (created_at) associate with each of these url. , Are the records sorted?
code :
select url, min(created_at)
from databaseTable
where blabala
group by url

Selecting distinct column of a distinct column using SQL Server


By : SharonYu
Date : March 29 2020, 07:55 AM
I wish did fix the issue. Put the values in the partition by that you want to be unique. So, I think you want userID, house there. The order by doesn't make a difference:
code :
with cte AS (
    select p.* 
           row_number() over (partition by userID, house order by house) AS seqnum
    from people p
)

select userid, house, numofppl, numofcars
from cte 
where seqnum = 1;

How to get distinct count of a column with respective to distinct values of another column in same table?


By : Rene Keijzer
Date : March 29 2020, 07:55 AM
I wish this help you I have marks table with student id, class, section, subject id, total marks and isPassed status (1=pass, 0=fail). I want total number of student in a class or section having isPassed status 1 in all subjects. My query looks like this: , Your SQL query should be like this:
code :
SELECT COUNT(student_id)
FROM marks
WHERE class_room_id = 10
AND student_id NOT IN (SELECT student_id FROM marks WHERE class_room_id = 10 AND isPassed = 0)
SELECT COUNT(DISTINCT student_id)
FROM tbl2
WHERE student_id NOT IN (SELECT student_id FROM tbl2 WHERE isPassed = 0)
SELECT student_id FROM tbl2 WHERE isPassed = 0
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