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Response [412] when using the requests python package to access this webpage, how to get around it?

By : Bruce Huang
Date : September 15 2020, 01:00 PM
wish help you to fix your issue That website require a valid Cookie in order to response back to you.
I've tried several ways such as calling the main website and then retrieving the Cookie under requests.Session() but the website is not allowing me to pass through.
code :
import requests

headers = {
    "User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:72.0) Gecko/20100101 Firefox/72.0",
    "Cookie": "Hm_lvt_5544783ae3e1427d6972d9e77268f25d=1578572654; Hm_lpvt_5544783ae3e1427d6972d9e77268f25d=1578572671; dataHide2=64fa0f2a-a6aa-43b4-adf0-ce901e8d1a37; FSSBBIl1UgzbN7N80S=sXE0qXcyGkTm4uVerLqfZyUU3XFMZzkm22k.eqVABLPe0eYMo3D8uX5ZJ07.7cCr; FSSBBIl1UgzbN7N80T=4aY.P74ZFvDef6i1BgsPAGpjsGOCcIHJFaOyshl4_fJ1WvTk1nqBkdG9PsyX3VRZcIuI8zdYiRJw4rEBQfx.Mv.GS_wT6Hzgiw.AY.UMP.Mw4iCKXGDzY1UeIH2gUd15impxzBVzZpN3MnSdqD0TUqcxSq0RrvIuE8RKT5pFLAqaNnVqtbeSACx43yIYtKJ41y8Isu6a6lNOlWNeaFJ8bx22pKm3lAIO.HIDhGSZqrUP76.q3i4Iux59f7dqJPuSRF90G1LSUBE8t8HrlWzBcSwJJJARX4Ioc0iHmHvdkVoigUitTRjLUHJM4ieOV1sLBDsq"

r = requests.get("http://wjw.hubei.gov.cn/", headers=headers)
<Response [200]>
import requests

headers = {
    "User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:72.0) Gecko/20100101 Firefox/72.0"}

with requests.Session() as req:
    r = req.get("http://www.hubei.gov.cn/")
    headers['Cookie'] = r.headers.get("Set-Cookie")
    for item in range(10):
        new = req.get("http://wjw.hubei.gov.cn/", headers=headers)

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How do I make the response from Python's requests package be a "file-like object"

By : user2110866
Date : March 29 2020, 07:55 AM
hop of those help? You could use the response.raw file object, but take into account that any content encoding (such as GZIP or Deflate compression) will still be in place unless you set the decode_content flag to True when calling .read(), which psycopg2 will not.
You can set the flag on the raw file object to change the default to decompressing-while-reading:
code :
response.raw.decode_content = True

How to access server response when Python requests library encounters the retry limit

By : Ni KA
Date : March 29 2020, 07:55 AM
I wish this helpful for you Checking out the urllib3 source, I discovered that the Retry object takes a named parameter called raise_on_status. True is the default. When set to False, running into the retry limit causes a response to be returned instead of an exception being thrown. The code below shows me causing an HTTPError (containing the Response) to be thrown by using the raise_for_status method on the Response, but one could just as easily use the Response directly.
code :
#!/usr/bin/env python

import requests
from requests.adapters import HTTPAdapter
from requests.packages.urllib3.util.retry import Retry
from requests.exceptions import HTTPError

def main():
    retry_policy = Retry(

    session = requests.Session()
    session.mount('http://', HTTPAdapter(max_retries=retry_policy))

        response = session.get('http://httpbin.org/status/418')
    except HTTPError as e:
        print e.response.status_code
        print e.response.content

if __name__ == '__main__':

-=[ teapot ]=-

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Empty response after submit a form with (requests) python package

By : shalman
Date : March 29 2020, 07:55 AM
it fixes the issue If You check request data using Firebug or some similar tool, You'd see that request data is actually in following format:
code :
Content-Disposition: form-data; name="email"

Content-Disposition: form-data; name="tagset"

Content-Disposition: form-data; name="style"

Content-Disposition: form-data; name="text"


Python Requests package: Handling xml response

By : Mohammad Mahjoub
Date : March 29 2020, 07:55 AM
may help you . requests does not handle parsing XML responses, no. XML responses are much more complex in nature than JSON responses, how you'd serialize XML data into Python structures is not nearly as straightforward.
Python comes with built-in XML parsers. I recommend you use the ElementTree API:

How can I access a peer's cert chain from a python-requests response/exception object?

By : Pedro Célestin
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , Take requests.get("") # stackoverflow's ip as an example:
code :
except requests.exceptions.SSLError as e:
    cert = e.args[0].reason.args[0]._peer_cert
except requests.exceptions.SSLError:
    import ssl
    import OpenSSL
    cert = ssl.get_server_certificate(('fpslinux1.finalphasesystems.com', 443))
    cert = OpenSSL.crypto.load_certificate(OpenSSL.crypto.FILETYPE_PEM, cert)
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