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Implementing a non-copyable C++ class


By : bonaf1de
Date : September 15 2020, 04:00 PM
This might help you Everything's working as expected.
Your code attempts two copies, and both approaches you took to making the class non-copyable succeeded. You can see that, because you got compilation errors.
code :
Foo myFoo1{ Foo() };
Foo myFoo2{ Foo("myFoo2") };
Foo myFoo1{};
Foo myFoo2{"myFoo2"};
Foo myFoo1;
Foo myFoo2("myFoo2");


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Extracting the copyable identity of the non-copyable object


By : user3098796
Date : March 29 2020, 07:55 AM
With these it helps It seems that +[NSValue valueWithPointer:] might be what you want. It stores the pointer itself in an object that conforms to NSCopying, so that you can use it as a dictionary key. Retrieve the pointer using pointerValue.

Non-Copyable Within Class


By : Marcelo Galvão
Date : March 29 2020, 07:55 AM
it should still fix some issue First of all, whether you can use C++11 or not is a game changer.
In C++11, you have the concept of move. Unlike copying, moving is not about duplicating but about transferring. All Standard containers were adapted to non-copyable classes that are movable.
code :
class Client {
public:
    Client(Client const&) = delete; // non copyable
    Client& operator=(Client const&) = delete; // non copy assignable

    Client(Client&&) = default; // movable
    Client& operator=(Client&&) = default; // move assignable

private:
    std::unique_ptr<sf::TcpSocket> _socket;
};

Can a non-copyable member be used as alternative to make an object non-copyable?


By : Sally Ackerman
Date : March 29 2020, 07:55 AM
help you fix your problem Since C++11, the proper idiom for making a class non-copyable is to = delete the copy constructor/assignment operator. That's what C++ programmers are told to do, and that's what other C++ programmers will expect to see when looking for that behavior in your class..
It's fine to have a subobject (member or base class) that is non-copyable, and thus your default copy constructor/assignment operator will be implicitly deleted. But you should only do this for a subobject that happens to be non-copyable. That is, you have a unique_ptr or mutex or whatever as a member because you need a unique_ptr or a mutex as class instance data. Not because you're using it as a hack to make the type non-copyable.

C++ non-copyable lambda behaves copyable?


By : user2652003
Date : March 29 2020, 07:55 AM
wish help you to fix your issue
Is there some exception for lambda's and copy constructability traits?

Does being trivially copyable imply being nothrow copyable?


By : IreneP
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , Alternatively, is there an example of a type with a copy constructor that can throw, but is nontheless trivial? And if not, does that imply that the is_nothrow_copy_constructible_v should be true whenever is_trivially_copy_constructible_v is true? ,
Does being trivially copyable imply being nothrow copyable?
code :
struct X {
    X(X&& ) = default;
    X(X const& ) = delete;
};
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