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Cassandra Insert/Update without duplication when you can't rely on the primary key or uuid


By : daisy123
Date : September 15 2020, 06:00 PM
it helps some times You can only really use the UUID as the partition key if you know if beforehand. You won't be able to insert new customers into the table if you don't have the UUID.
Based on your description, you use the UUID as the unique ID for the rest of your system so it really is the perfect partition key. You will however need to find a solution for the situations where you don't have the customer's UUID. Cheers!
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Cassandra - How to insert an UUID


By : DingDong
Date : March 29 2020, 07:55 AM
may help you . Same problems as this. Same solution :)
(short version: you are confusing row key with column name/key)

How can I insert to Cassandra with CQL, to table with only primary key, using UPDATE?


By : John P
Date : March 29 2020, 07:55 AM
like below fixes the issue Not sure if you can do this with update like that. But why not just create a new dummy column that you never use for anything else? Then you could do
code :
update users set dummy=1 where user_id=3 and website_id=2;

When insert uuid (Type UUID) into mysql report duplicate entry for key PRIMARY


By : Christian Cruz
Date : March 29 2020, 07:55 AM
To fix this issue it said that in table posts_categories it has the duplicate entry for key PRIMARY
Don't make post_uuid the primary key of posts_categories.

Scala Spark Cassandra update or insert rows on primary key match


By : Ankit Singh
Date : March 29 2020, 07:55 AM
I wish did fix the issue. I think you should be able to just directly write the data to cassandra and not have to worry about it, assuming all primary keys are the same.
Cassandra's inserts are really "insert or update" so I believe when you insert one side of a join, it will just leave some columns empty. Then when you insert the other side of the join, it will update that row with the new columns.

Cassandra - Ignore a Primary Key UUID on Where clausure


By : Adelina
Date : March 29 2020, 07:55 AM
Any of those help This is simply not possible in cassandra as it would require to scan through all records
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