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Why is my basic exponent function not working?


By : Chris Oh
Date : September 15 2020, 07:00 PM
this will help I am trying to take input for an exponent function but it doesn't give an output. , Range expects integer type, not float.
code :
range(10)
#range(1,10)
range(10.0)
#TypeError: 'float' object cannot be interpreted as an integer
def exp_func(base,exponent):
    result = 1
    for index in range(0,exponent):
        result*=base
    return result

base = float(input("Enter base:"))
exponent = int(input("Enter exponent:"))

print(exp_func(base,exponent))
def exp_func(base,exponent):
    return base ** exponent


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Extract modulus n, private exponent and public exponent in Python cryptography library


By : Héctor G.
Date : March 29 2020, 07:55 AM
I wish this help you I am using Python cryptography library and I need to encrypt something with RSA. It all works great, except one thing. , You can access using public_numbers() and private_numbers()
code :
 public_key.public_numbers()
 private_key.private_numbers()
In [13]: [a for a in dir(public_key) if not a.startswith("_")]
Out[13]: ['encrypt', 'key_size', 'public_bytes', 'public_numbers', 'verifier']

In [14]: [a for a in dir(private_key) if not a.startswith("_")]
Out[14]: 
['decrypt',
 'key_size',
 'private_bytes',
 'private_numbers',
 'public_key',
 'signer']


In [15]: [a for a in dir(private_key.private_numbers()) if not a.startswith("_")]
Out[15]: ['d', 'dmp1', 'dmq1', 'iqmp', 'p', 'private_key', 'public_numbers', 'q']

In [16]: [a for a in dir(public_key.public_numbers()) if not a.startswith("_")]
Out[16]: ['e', 'n', 'public_key']

In [17]: [a for a in dir(private_key.private_numbers().public_numbers) if not a.startswith("_")]
Out[17]: ['e', 'n', 'public_key']

Using arrays to do basic calculations with negative exponent


By : SteveB
Date : March 29 2020, 07:55 AM
wish helps you I'm trying to write a function which outputs the correct result when multiplying a number by a negative power of ten using arrays and split() method. For example the following expressions get the right result: 1x10^-2 = 0.01 1x10^-4 = 0.0001. , The problem is where you push the decimal point .
instead of

Why does `math.ldexp` raise OverflowError for exponent>1024, but not for exponent<-1073?


By : Ferenc Papp
Date : March 29 2020, 07:55 AM
To fix this issue IEEE floating point arithmetic is known to have some degree of imprecision. 0.0 is a value which is very close to math.ldexp(0.5, -1074). However, there is no valid way of expressing a value that is close to math.ldexp(0.5, 1025), so I would assume that's why it raises an Exception.

java:39: cannot find symbol symbol : method exponent(double,int) else { return base * exponent(base, exponent - 1);}


By : Joey Lin
Date : March 29 2020, 07:55 AM
this will help , Instead of

How to store modulus, public exponent and private exponent securely on Android?


By : Chethan Kumar Adiman
Date : March 29 2020, 07:55 AM
wish of those help Use the Keystore System.
setEntry() allows you to store any object implementing KeyStore.Entry. You can simply implement your own subtype if you need to store data that doesn't fit the defaults. (There's RSAPrivateCrtKey though, which you can store in a PrivateKeyEntry.)
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