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Filter array, obtaining a list


By : Mark
Date : September 15 2020, 10:00 PM
help you fix your problem Assuming the initial JSON you provided is actually meant to be an object consisting of properties that are arrays (because JSON arrays cannot have properties), you would simply use Array.prototype.map on one of the object's properties:
code :
   const dataObject = {
"q1": [{ "key_api": 86, "question_api": "q1", "answer_api": "a1" }, { "key_api": 87, "question_api": "q1", "answer_api": "a2" }, { "key_api": 88, "question_api": "q1", "answer_api": "a3" }, { "key_api": 89, "question_api": "q1", "answer_api": "a4" }],
"q2": [{ "key_api": 90, "question_api": "q2", "answer_api": "a5" }, { "key_api": 91, "question_api": "q2", "answer_api": "a7" }, { "key_api": 92, "question_api": "q2", "answer_api": "a9" }],
"q3": [{ "key_api": 93, "question_api": "q3", "answer_api": "a1" }, { "key_api": 94, "question_api": "q3", "answer_api": "a2" }, { "key_api": 95, "question_api": "q3", "answer_api": "a3" }, { "key_api": 96, "question_api": "q3", "answer_api": "a4" }],
"q4": [{ "key_api": 97, "question_api": "q4", "answer_api": "a10" }, { "key_api": 98, "question_api": "q4", "answer_api": "a11" }, { "key_api": 99, "question_api": "q4", "answer_api": "a12" }, { "key_api": 100, "question_api": "q4", "answer_api": "a13" }]
};
console.log(dataObject['q4'].map(item => item.answer_api));
const dataObject = {
    "q1": [{ "key_api": 86, "question_api": "q1", "answer_api": "a1" }, { "key_api": 87, "question_api": "q1", "answer_api": "a2" }, { "key_api": 88, "question_api": "q1", "answer_api": "a3" }, { "key_api": 89, "question_api": "q1", "answer_api": "a4" }],
    "q2": [{ "key_api": 90, "question_api": "q2", "answer_api": "a5" }, { "key_api": 91, "question_api": "q2", "answer_api": "a7" }, { "key_api": 92, "question_api": "q2", "answer_api": "a9" }],
    "q3": [{ "key_api": 93, "question_api": "q3", "answer_api": "a1" }, { "key_api": 94, "question_api": "q3", "answer_api": "a2" }, { "key_api": 95, "question_api": "q3", "answer_api": "a3" }, { "key_api": 96, "question_api": "q3", "answer_api": "a4" }],
    "q4": [{ "key_api": 97, "question_api": "q4", "answer_api": "a10" }, { "key_api": 98, "question_api": "q4", "answer_api": "a11" }, { "key_api": 99, "question_api": "q4", "answer_api": "a12" }, { "key_api": 100, "question_api": "q4", "answer_api": "a13" }]
};
Object.keys(dataObject).forEach(key => {
    console.log(dataObject[key].map(item => item.answer_api));
})


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Issue obtaining minimum value of list/array


By : Vilko
Date : March 29 2020, 07:55 AM
should help you out I'm having a weird issue, at least I can't explain the reason for this behaviour. , You used a list comprehension:
code :
x1 = [rand_data() for i in range(1)]
x1 = rand_data()

Obtaining the index of the largest element of an array without also obtaining the value


By : Pierrot
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further You can always put a ~ for any return you don't want, so, in your case, you'd have [~,index] = max(A).

Using filter on Swift Array gives "cannot invoke filter with an argument list of type (Object) throws -> Bool,&q


By : user6236302
Date : March 29 2020, 07:55 AM
Any of those help The error message might be misleading. The result of filter is always an array
code :
var books = [Book]()

let fetchRequest: NSFetchRequest<Book> = Book.fetchRequest()
if let fetchResults = try? managedObjectContext.fetch(fetchRequest) {
    books = fetchResults.filter { $0.title == defaultBookTitle }
}
var books = [Book]()

let fetchRequest: NSFetchRequest<Book> = Book.fetchRequest()
fetchRequest.predicate = NSPredicate(format:"title = %@", defaultBookTitle)
do {
   books = try managedObjectContext.fetch(fetchRequest)
} catch {
  print(error)
}

Swift: use filter function on array of dictionaries? Error: Cannot invoke 'filter' with an argument list of type


By : D. Gordon
Date : March 29 2020, 07:55 AM
Any of those help Filtering [[String:AnyObject]] (a.k.a. Array>) results in another [[String:AnyObject]]. You're trying to assign this to a var of type AnyObject, which is not allowed in Swift 3, since arrays are structs, not objects.
Make a type-safe struct or object to hold this data, rather than a dict.
code :
let dictArray = networkData["dicts"] as! [[String:AnyObject]]
let filteredDicts = dictArray.filter{ ($0["id"] as! String) != sample.getId() }         
localData["dicts"] = filteredDicts

Obtaining a list of arrays by diagonally traversing a 2D array with left-leaning diagonal sections?


By : lesonapt
Date : March 29 2020, 07:55 AM
I hope this helps .
Trying to iterate left-leaning diagonals makes it difficult to always know the length of the array I am using. Especially since the new char[] arrays I create will be of different lengths.
code :
int newCharArrayLength = Math.min(height - i, width - j);
private static List<char[]> getDiagonalsList(char[][] arr) {
    List<char[]> ans = new ArrayList<>();
    int height = arr.length;
    int width = arr[0].length;
    int numberOfDiagonals = arr.length + arr[0].length - 1;

    for (int diagonalIdx = 0; diagonalIdx < numberOfDiagonals; diagonalIdx++) {
        int i = Math.max(diagonalIdx - width + 1, 0);
        int j = Math.max(width - diagonalIdx - 1, 0);
        int currentDiagonalLength = Math.min(height - i, width - j);
        int idx = 0;

        char[] charArr = new char[currentDiagonalLength];
        while (i < height && j < width)
            charArr[idx++] = arr[i++][j++];

        ans.add(charArr);
    }

    return ans;
}
public static void main(String[] args) {
    char[][] arr = {
            {'a', 'b', 'c', 'd', 'e', 'q'},
            {'f', 'g', 'h', 'i', 'j', 'w'},
            {'k', 'l', 'm', 'n', 'o', 'e'},
            {'p', 'q', 'r', 's', 't', 'r'},
            {'u', 'v', 'w', 'x', 'z', 't'}};

    for (char[] diag : diagonal(arr))
        System.out.println(diag);
}
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