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Get first day of first month of previous year in yyyy-mm-dd format


By : Pierre Tapia
Date : September 15 2020, 11:00 PM
seems to work fine You can use DATEFROMPARTS() function in SQL Server for creating date from given year, month and date in integer as shown below. To get the previous year you can use Year() function and subtract 1 from that. First date and month is always 1 so it has been hard-coded here.
code :
declare @IntYear int = Year(Getdate()) - 1 --Previous Year
Select datefromparts(@Intyear, 1, 1)


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how to select month and year in from dd/mm/yyyy 00:00 format mysql


By : Marilza Mota
Date : March 29 2020, 07:55 AM
may help you . Choosing the right datatype has much gravity.
Since you are storing date time in varchar datatype I would suggest to move it to the timestamp type.
code :
UPDATE 
your_table 
SET column1 = STR_TO_DATE(column1,'%d/%m/%Y %H:%i');
ALTER TABLE your_table MODIFY column1 timestamp;
select date_format (column1, '%m/%Y') from table1

How to calculate previous month from current month in SSRS with format MM-YYYY


By : Arebear
Date : March 29 2020, 07:55 AM
I hope this helps . i want to calculate previous months from current month in SSRS with the format like this: MM-YYYY, for example: 10-2016,11-2016 , You can do it like this for month previuos to current month:
code :
=Format(DateAdd(DateInterval.Month, -1, Today), "MM-yyyy")

Get first day of previous month in YYYY-MM-DD format


By : Mickey Zelansky
Date : March 29 2020, 07:55 AM
wish help you to fix your issue You can use the EOMONTH function for this. This function is supposed to return the end of month so add one day to result:
code :
SELECT DATEADD(DAY, 1, EOMONTH(GETDATE(), -2)) -- returns 2019-07-01 on 2019-08-28 01:02:03.004

How to extract month and year from mm/yyyy format in R?


By : Fazal
Date : March 29 2020, 07:55 AM
Any of those help There are a number of ways. You can use the base grep functions, but I prefer the stringr library.
code :
# Using RegEx to find any characters from the start of the string that are not
# a forward slash, then stop once a forward slash is found
df$Month <- stringr::str_extract(df$`Month & Year`,"^[^/]+") # Edited to fix mistake
# Grabbing the last 4 characters of a string
df$Year <- stringr::str_sub(df$`Month & Year`,-4,-1)

Get last day of previous month in yyyy-mm-dd format


By : Paul Bituin
Date : March 29 2020, 07:55 AM
I hope this helps . Use the EOMONTH function along with FORMAT:
code :
SELECT FORMAT(EOMONTH(CURRENT_TIMESTAMP, -1), 'yyyy-MM-dd')
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