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Async/Await inside Reduce


By : Kirk Patrick Edullan
Date : September 16 2020, 01:00 AM
To fix this issue You can create an array of promises and then use Promise.all to resolve them. If any request fails Promise.all will stop processing the remaining requests.
code :
const papersPromises = page.concepts.map(cur => 
    getPageData(`papers/${ cur.paperID }`, 'md')
)

const result = await Promise.all(papersPromises)
// result will be an array with the results


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Async/Await inside Array function reduce


By : stagiaire
Date : March 29 2020, 07:55 AM
this will help The code inside the promise gets executed when you call the function that returns the promise:
code :
// Parallel Execution
var arr1 = [2,3,4].reduce((prev,next)=>{
    return prev.concat(proot(next))
},[])
var arr = [2,3,4].map((n) => proot(n));
Promise.all(arr).then((values) => {})
var arr = [2,3,4].map(async (n) => await proot(n));

NodeJs - Async/Await inside async/await


By : Kaustubh Gajare
Date : March 29 2020, 07:55 AM
Hope that helps Change the inner await to a return statement, otherwise prices.map() is generating an array of entries that are undefined instead of promises.
Since Transport#save() does not return a promise, you'll need to wrap it with a Promise constructor since it is a callback-style API, or refer to the documentation which may perhaps explain how to instead return a promise.
code :
// ...
obj.normal = price.normal;

return new Promise((resolve, reject) => {
  new Transport(obj).save((err: any, doc: any) => {
    console.log('Middle');

    if (err) return reject(err);

    price.transport_id = doc._id;
    resolve(price);
  });
});

Printing simple text using fetch and await. Why do I need more than one await inside an async function?


By : Dupree Stylze
Date : March 29 2020, 07:55 AM
it fixes the issue Taking a step back, await accepts a promise as its argument. Looking at the docs for fetch. fetch() returns a promise. response.headers is not a promise. response.text() returns a promise.
Given all of that, await response.headers is not necessary, but your other two are.

Can not use await inside a Parallel.Foreach . error :- The 'await' operator can only be used within an async lambda expr


By : Beth Adams
Date : March 29 2020, 07:55 AM
To fix this issue Parallel.ForEeach is not designed to work with asynchronous functions, you need to use more modern classes like the ones in TPL Dataflow. You get it by installing the NuGet package to your project Microsoft.Tpl.Dataflow. You could recreate your previous code as

How to reduce use of await keyword in async await while maintaining execution order


By : simeon.it
Date : March 29 2020, 07:55 AM
will help you This will guarantee the sequential execution order you wished for.
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