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#define statement for address of memory

By : Fei.Y
Date : September 16 2020, 04:00 AM
wish helps you It is usually used to access hardware registers mapped into the address space, or some particular memory addresses
Hardware registers should be defined as volatile as registers can change without any program activity (as they are changed by the hardware).
code :
#define GPIOREGA ((volatile uint32_t *) 0x6FC0) 
#define __IO volatile

typedef struct
  __IO uint32_t MODER;    /*!< GPIO port mode register,               Address offset: 0x00      */
  __IO uint32_t OTYPER;   /*!< GPIO port output type register,        Address offset: 0x04      */
  __IO uint32_t OSPEEDR;  /*!< GPIO port output speed register,       Address offset: 0x08      */
  __IO uint32_t PUPDR;    /*!< GPIO port pull-up/pull-down register,  Address offset: 0x0C      */
  __IO uint32_t IDR;      /*!< GPIO port input data register,         Address offset: 0x10      */
  __IO uint32_t ODR;      /*!< GPIO port output data register,        Address offset: 0x14      */
  __IO uint32_t BSRR;     /*!< GPIO port bit set/reset register,      Address offset: 0x18      */
  __IO uint32_t LCKR;     /*!< GPIO port configuration lock register, Address offset: 0x1C      */
  __IO uint32_t AFR[2];   /*!< GPIO alternate function registers,     Address offset: 0x20-0x24 */
} GPIO_TypeDef;

#define PERIPH_BASE           0x40000000U /*!< Peripheral base address in the alias region                                */

#define AHB1PERIPH_BASE       (PERIPH_BASE + 0x00020000U)
#define GPIOA_BASE            (AHB1PERIPH_BASE + 0x0000U)

#define GPIOA               ((GPIO_TypeDef *) GPIOA_BASE)
GPIOA -> MODER |= (1 << 15);

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If-Statement in C memory address

By : ysf6a2
Date : March 29 2020, 07:55 AM
Does that help a==0x6634522 checks whether a is equivalent to the hexadecimal 0x6634522 ( (6634522)16 = (107169058)10) ) or not. It is checking the value stored in a, not the address of a (&a).

Define pointer to memory address and print contents C++

By : BA_Wafa
Date : March 29 2020, 07:55 AM
I wish this help you An interesting little problem. One that should occur to every programmer sooner or later, either out of curiosity or cussedness.
Essentially four parts.
code :
int address = 0x1000;
int* pcontent = (int*)address;
int content = *pcontent;
printf ("Address %p: content %08x\n", pcontent, content);

understanding a c #define that returns a value at a memory address

By : Djilyes Edition Univ
Date : March 29 2020, 07:55 AM
this will help *(addr) returns the value stored at addr.
The above code looks self explanatory. If you dry run.
code :
unsigned char
unsigned char *
(unsigned char *) (ptr)
(*(unsigned char *)(ptr))

Edit Memory Address Via C#, How to set the statement?

By : Hanna SRS
Date : March 29 2020, 07:55 AM
I wish did fix the issue. i want to edit an active app (edit a memory address),

If I define an array in if statement then does memory get allocated?

By : Ramu V
Date : March 29 2020, 07:55 AM
wish of those help It is reserved on the stack at run-time (assuming a non-trivial condition - in your case, the compiler would just exclude the else part). That means it only exists inside the scope block (between the {}).
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