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why can't we add object property names using template strings


By : Prateek Goyal
Date : September 16 2020, 06:00 AM
To fix the issue you can do You need a computed property name.
code :
var x = "hiWithInterpolation";
a = {
    ...a,
    [`${x}`]: "helloWithINterPolation"
};


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Access an object's property names in a Blaze template


By : user3902502
Date : March 29 2020, 07:55 AM
Does that help This will be helpful:
http://meteorcapture.com/spacebars/
code :
<template name="profile">
  <ul>
    {{#with info}}
      <li>{{Name}}</li>
      <li>{{Age}}</li>
      <li>{{Location}}</li>
    {{/with}}
  </ul>
</template>
Template.profile.helpers({
  info: {
    Name: 'Bob Dinkleberg',
    Age: 45,
    Location: 'Earth, Milky Way'
  }
});
Template.profile.helpers({

  info: function(){

    return {
      Name: 'Bob Dinkleberg',
      Age: 45,
      Location: 'Earth, Milky Way'
    };

  }

});
Template.content.helpers({

  info: function(){
    var obj = {
      Name: 'Bob Dinkleberg',
      Age: 45,
      Location: 'Earth, Milky Way'
    };
    var arrayOfObjects = [];

    // creating an array of objects
    for (key in obj){
      arrayOfObjects.push({key: key, value: obj[key]});
    };
    console.log("This is the array of objects: ", arrayOfObjects);
    return arrayOfObjects;
  },

});
{{#each info}}
    {{value}}
{{/each}}

Create object with dynamic property names based on strings


By : user2728031
Date : March 29 2020, 07:55 AM
I wish this helpful for you Just loop over the items, and grab the item and push the value onto a new object:
code :
const items = [
{"id":4,"user_id":1,"business_id":2,"branch_id":3,"type":"service","item":"Typing","unitPrice":100,"bulkUnit":20,"bulkUnitPrice":80,"availableUnits":"NA","created_at":"2019-05-03 11:36:33","updated_at":"2019-05-03 11:36:33"},
{"id":5,"user_id":1,"business_id":2,"branch_id":3,"type":"service","item":"Printing","unitPrice":70,"bulkUnit":50,"bulkUnitPrice":40,"availableUnits":"NA","created_at":"2019-05-03 11:37:29","updated_at":"2019-05-03 11:37:29"}
]

let result = {} 
items.forEach(i => { result[i.item] = null })
console.log(result)

Get array of object property names in ARM template


By : bauerInHsv
Date : March 29 2020, 07:55 AM
I hope this helps you . There is not a straightforward way of doing this as there is no function to return the properties of an object. I was able to accomplish it by converting the the object to a string and then parsing it to find the property names. It should work as long as you don't have commas in your property values. You could probably add some checks to handle that case as well if needed.
code :
{
    "$schema": "https://schema.management.azure.com/schemas/2019-04-01/deploymentTemplate.json#",
    "contentVersion": "1.0.0.0",
    "parameters": {
        "testSettings": {
            "type": "object",
            "defaultValue": {
                "a": "demo value 1",
                "b": "demo value 2"
            }
        }
    },
    "variables": {
        "delimiters": [","],
        "settingArray": "[split(replace(replace(replace(string(parameters('testSettings')), '{', ''), '}', ''), '\"', ''), variables('delimiters'))]",
        "propNameArray": {
            "copy": [
                {
                    "name": "copyPropertyNames",
                    "count": "[length(variables('settingArray'))]",
                    "input": "[substring(variables('settingArray')[copyIndex('copyPropertyNames')], 0, indexOf(variables('settingArray')[copyIndex('copyPropertyNames')], ':'))]"
                }
            ]
        }
    },
    "resources": [],
    "outputs": {
        "paramOutput": {
            "type": "array",
            "value": "[variables('propNameArray').copyPropertyNames]"
        }
    }
}

JSON.stringify converts object's property names into strings


By : yuan chen
Date : March 29 2020, 07:55 AM
wish helps you This looks like the right output.
In the wiki the example looks the same WIKI JSON

Using Template Strings to get object property


By : Nikunj Keswani
Date : March 29 2020, 07:55 AM
will be helpful for those in need // why it dont give output as soni, Angular 2 using typescript , Use the other single quote:
code :
let xx = `${u.lastname}`;
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