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How to call methods in functional interfaces without .Method()

By : Henry Y
Date : September 16 2020, 10:00 AM
To fix this issue It's possible like this, exploiting the rules around the meaning of a name:
code :
static int F(double d) {
  return 0;

static void G() {}

static class X {
  void method();

public static void main(String[] args) {
  Consumer<X> F;
  Runnable G;

  F = X::Method; int i = F(0.0); G = new X()::Method; G();
class X {
  static int F(double x) {
    return 0;

  static int Method(double x) {
    return F(x);

  static void G() {}

  void Method() {

  public static void main(String[] args) {
    DoubleToIntFunction F;
    Runnable G;

    F = X::Method; int i = F(0.0); G = new X()::Method; G();

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static vs default method - Functional interfaces

By : George.T
Date : March 29 2020, 07:55 AM
this one helps. When you are creating the anonymous class, you actually provide an implementation for your abstract method doFunction() from FunctionalIntf interface. So when you are using this line of code:
code :
Runnable r = new Runnable() {
    public void run() {
        System.out.println("I'm Runnable!");

Functional Interface vs Interfaces with single methods like Runnable

By : Mr.Tiger
Date : March 29 2020, 07:55 AM
hope this fix your issue There is no difference, the docs for FunctionalInterface state:

Disambiguate overloaded methods that accept different functional interfaces

By : hvs.1509
Date : March 29 2020, 07:55 AM
wish help you to fix your issue I have the following available methods in a Utils class: , From the "Effective Java" by Joshua Bloch:
code :
<U> U withTxFunction(Function<OrientGraph, U> fc);

void withTxConsumer(Consumer<OrientGraph> consumer);
mapToDouble(IntToDoubleFunction mapper);

mapToLong(IntToLongFunction mapper);
Function<T, R> func  = g -> anotherMethod(g);

Consumer<T> consumer = g -> anotherMethod(g); // here you just ignore the return value

<T> T anotherMethod(T t) { ... }
withTx(function) OR withTx(consumer) ... ?

Will java allow to use functional interfaces as methods?

By : Suk Choi
Date : March 29 2020, 07:55 AM
To fix this issue Your proposition
What you propose has been discussed on the lambda-dev mailing list before:

Functional Programming: is foldLeft is the parent method of all functional methods such as foldRight, map, filter

By : Andres Campos
Date : March 29 2020, 07:55 AM
hop of those help? In general, no, foldLeft is not the "father" of all other methods, because there are many collections other than List. For example, you can not implement Stream.map via Stream.foldLeft because foldLeft does a full traversal but map should not traverse the stream because of its laziness (it can be potentially infinite).
As to the List you are mostly right. However, some methods will be extremely inefficient if implemented via foldLeft. Consider list.drop(1). It should just return the tail of the list, but foldLeft would do a full traversal.
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