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Remove redundant String from array string


By : T.L
Date : September 16 2020, 11:00 AM
seems to work fine I'm assuming that your algorithm is:
Break each element in your input into words (separated by spaces) If we've seen all of those words before (case-insensitive), then ignore that element Otherwise, add that element to the output, and remember all of those words
code :
var input = new string[] {"Financial banking", "mobile application", "customer account opening", "financial", "banking", "mobile", "application", "account banking"};
var wordsSeen = new HashSet<string>(StringComparer.InvariantCultureIgnoreCase);
var result = new List<string>();

foreach (var item in input)
{
    var words = item.Split(' ');

    // If all of the elements in 'words' are present in 'wordsSeen', ignore this item
    if (wordsSeen.IsProperSupersetOf(words))
        continue;

    result.Add(item);

    // Add all of these words to 'seen'
    wordsSeen.UnionWith(words);
}


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Remove redundant whitespace from string (in-place)


By : user1772549
Date : March 29 2020, 07:55 AM
may help you . Try just doing this yourself character by character on a piece of paper and work out what it is you are doing first, then translate that into code.
If you are still having trouble, try doing something simpler first, for example just copying a string character for character without worrying about the "remove duplicate spaces" part of it - just to make sure that you haven't made a silly mistake elsewhere.

R remove redundant parentheses from formula string or expression


By : Hernán Martínez
Date : March 29 2020, 07:55 AM
this one helps. I have many formula strings similar to this: , Here are a couple of approaches:
R parsing
code :
rmParen <- function(e) {
    if (length(e) > 1) {
        if (identical(e[[1]], as.symbol("("))) e <- e[[2]]
        if (length(e) > 1) for (i in 1:length(e)) e[[i]] <- Recall(e[[i]])
    }
    e
}

s <- "( ((  A  ) *  J ) - ((  J  ) *  G  ) ) /  Z "
rmParen(parse(text = s)[[1]])
(A * J - J * G)/Z
library(Ryacas)

s <- "( ((  A  ) *  J ) - ((  J  ) *  G  ) ) /  Z "
Simplify(s)
expression((A - G) * J/Z)

Remove redundant html tags from string


By : Oggie
Date : March 29 2020, 07:55 AM
To fix the issue you can do If i'd need to manipulate HTML, i'd use a HTML-parser like HtmlAgilityPack, not string methods or regex. Here is an example that removes all br from the end:
code :
string html = "<li><ol>  **Text/List**  </li></ol><p><br></p><br><br>";
var doc = new HtmlAgilityPack.HtmlDocument();
doc.LoadHtml(html);
var brToRemove = doc.DocumentNode.Descendants().Reverse().TakeWhile(n => n.Name == "br");
foreach (HtmlNode node in brToRemove)
    node.Remove();

using (StringWriter writer = new StringWriter())
{
    doc.Save(writer);
    string result = writer.ToString();
}
<li><ol>  **Text/List**  </ol></li><p>
html = "<ol><li>TEXT</li></ol><p><br></p><p><br></p>&nbsp;";
var tagsToRemove = new Dictionary<string, IEnumerable<string>>
{
    { "br", Enumerable.Empty<string>() }, { "p", Enumerable.Empty<string>() }, { "#text", new[] { "&nbsp;" } }
};
var brToRemove = doc.DocumentNode.Descendants()
    .Reverse()
    .TakeWhile(n => tagsToRemove.ContainsKey(n.Name) 
                 && tagsToRemove[n.Name].DefaultIfEmpty(n.InnerText).Contains(n.InnerText));
<ol><li>TEXT</li></ol>

How to remove specific part(redundant querystring) of string in php?


By : andronite98
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further You ca use the following regex(DEMO):
code :
(\?(?<=\?).*(?=\?))
$str = "localhost.com/en_ar/body?products_type=235&treatment=132?product_type=235&treatment=132&__from_store=en_bh";
$newStr = preg_replace('/(\?(?<=\?).*(?=\?))/', '', $str);
var_dump($newStr);

php remove redundant words from string range


By : Ali Prince
Date : March 29 2020, 07:55 AM
I wish did fix the issue. The hardest part here is to split the input into tokens, as it's not structured well enough. I used a recursive function to sequentially clean the string of the first element duplicates. It works correctly for this input, but I am not sure, that it's 100% correct, as input structure is unclear:
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