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remove duplicates without using remove or fromkeys;list slicing; python


By : Harold
Date : September 16 2020, 04:00 PM
wish help you to fix your issue I'm trying to remove duplicates in a list with iteration and slicing (without .remove or fromkeys etc) and keep having wrong result. , You could just put the new elements into a new list like,
code :
>>> x
['a', 'n', 'a', 'a', 'n']
>>> y = []
>>> 
>>> for e in x:
...   if e not in y:
...     y.append(e)
... 
>>> y
['a', 'n']
>>> list(set(x))
['n', 'a']


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How to remove duplicates from a list python


By : Jeremy Lombogia
Date : March 29 2020, 07:55 AM
I wish this helpful for you You can use a collections.Counter for your use case, it is a dict subclass for counting hashable objects (example - characters in a string) . Example -
code :
>>> from collections import Counter
>>> c = Counter('hello')
>>> c
Counter({'l': 2, 'h': 1, 'o': 1, 'e': 1})
>>> for i,x in c.items():
...     print('{} - {}'.format(i,x))
...
l - 2
h - 1
o - 1
e - 1
input_text = input('Enter some text: ')
s = input_text.lower()
seen = set()
for c in s:
     if c not in seen:
         print(c, s.count(c))
         seen.add(c)

python iterate over a list and remove any duplicates found within lists inside a dictionary and remove the duplicates


By : Joe Stubbs
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further You are accessing the dict values in a wrong way. Take a look at the following:
code :
players = {'ray': [1,2,3,6,7,8,], 'al':[1,2,3,4,8,9,]}
lotto =[1,2,3,4,5,6,]

for p, val in players.items():  
    for num in lotto:
        if num in val:
            players[p].remove(num)

print (players)  # {'al': [8, 9], 'ray': [7, 8]}
players = {'ray': [1,2,3,6,7,8], 'al':[1,2,3,4,8,9]}
lotto = [1,2,3,4,5,6]
lotto = set(lotto)

for p, val in players.items():
    players[p] = list(set(val) - lotto)

print (players)  # {'ray': [8, 7], 'al': [8, 9]}
players = {k: list(set(val) - lotto) for k, v in players.items()}

Remove duplicates from a list and remove respective elements from second list in python


By : Harpreet Singh
Date : March 29 2020, 07:55 AM
I wish did fix the issue. One thing you can do is zip Name and Number together and then make a dict. Since a dict hashes only based on the value of the key, then the value remains still associated with the name, but is otherwise left untouched:
code :
name_dict = dict(zip(names, numbers))
new_names, new_numbers = zip(*list(name_dict.items()))

Remove duplicates from a list in Python


By : Kiran Kumar Gajjala
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , You have one element in a list. If you expected it to be treated as separate elements, you need to explicitly split it.
You could split the string on the ',' comma character into a list with str.split():

Cannot remove duplicates from a list using Python


By : Nipun
Date : March 29 2020, 07:55 AM
it should still fix some issue The problem you have is that csv_in is a list of lists and list is not hashable datatype. In order to get around the issue you can do the following:
code :
csv_in = list(set([tuple(row) for row in csv_in]))
csv_in = [list(element) for element in set([tuple(row) for row in csv_in])]
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