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Why does this result in a syntax error? Is it something to do with the Boolean value?


By : Shady El Rifaii
Date : September 16 2020, 06:00 PM
wish helps you If you don't see a syntax error in the line of code in the error message, check the lines above it.
You're missing a closing parenthesis in the call to print on line 2. Fixed:
code :
def less0(x):
    print(bool(x <= 0))
def less0(x):
    return x <= 0
print(less0(10))


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How to write correct expression to result to Boolean? (Cannot cast from boolean to Boolean)


By : 胡祥坤
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , I am experiencing difficulties with an expression that should result in showing or hiding a band in an iReport. , Are you looking for...
code :
showDetailGroup = Boolean.valueOf( (mainGroupInt.intValue() != 0 && subGroupInt.intValue() != 0) || 
                                   (mainGroupInt.intValue() != 0 && showDetailGroup.booleanValue()) )

Error in SQL Syntax. What would be the proper solution or right syntax to use for a successful result?


By : Ayprince
Date : March 29 2020, 07:55 AM
To fix the issue you can do MySQL said: , TIMESTAMP shouldn't have length
code :
CREATE TABLE  `activity_points` (
 `fk_user_id` INT( 10 ) NOT NULL DEFAULT  '0',
 `date` DATE NOT NULL DEFAULT  '0000-00-00',
 `points` INT( 10 ) NOT NULL DEFAULT  '0',
 `lastupdate` TIMESTAMP NOT NULL
) ENGINE = MYISAM ;

Syntax error on boolean declaration


By : KONG SOPENH
Date : March 29 2020, 07:55 AM
wish help you to fix your issue You have one error that jump out at me. Note that if you have a syntax error, most compilers will freak out and mark everything past the actual error as errors. The best way to debug accidental syntax errors is to look at the first error :)
code :
boolean = b1, b2;
[Type] [Variable Name] | ,[Additional Vars];
private String decode(char c) {

 switch (c) {

    case 'A': case 'B': case 'C': return "2";

    case 'D': case 'E': case 'F': return "3";

    case 'G': case 'H': case 'I': return "4";

    case 'J': case 'K': case 'L': return "5";

    case 'M': case 'N': case 'O': return "6";

    case 'P': case 'Q': case 'R': case 'S': return "7";

    case 'T': case 'U': case 'V': return "8";

    case 'W': case 'X': case 'Y': case 'z': return "9";

    default: return "";

    }

}
private static final Map<Char, String> myDecodeLookup = new Hashmap<Char,String>();

static{ //initializer block
    myDecodeLookup.put('A', "2");
    myDecodeLookup.put('B', "2");
    //and so and and so forth
}

private String decode(char c) throws KeyNotFoundException{
   return MyClassName.myDecodeLookup.get(c); //you should code this to support the keynotfoundexception that this might throw, or not.
}

Syntax error, boolean given


By : Arielson Ferreira
Date : March 29 2020, 07:55 AM
will help you mysql_query returns false on failure of the query. I like to use this instead of mysql_query:

Syntax for passing result of boolean evaluation in an array?


By : nguyenlehai
Date : March 29 2020, 07:55 AM
Does that help I'm not sure if this is an angular-centric question or just plain old JS syntax question. I'm obviously getting rusty as this feels like a dumb question but... , Sure, use either boolean algebra :
code :
isSelected: a === b
isSelected: a === b ? 1 : 0
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