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Is it possible to move the last character of a column to the first character of another column in excel or using python


By : Jdo web
Date : September 16 2020, 11:00 PM
To fix this issue Good afternoon , I was wondering if it was possible to move the last character of Column A to the first character of column B using excel or maybe even python. I know how to remove the last character in excel but i dont know how to go about adding it to another column? , In Excel:
Define column C with the following formula:
code :


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How do you replace a specific character in Column A to values in Column B in Excel?


By : Neron Nikata
Date : March 29 2020, 07:55 AM
may help you . Try the following (you can remove some vars that were included for debugging purposes):
code :
Sub test()
    Dim rng As Range, cl As Range
    Set rng = Range("A1:A4")
    Dim cl1 As Range, cl2 As Range
    For Each cl1 In rng
      Set cl2 = cl1.Offset(0, 1)
      Dim ival As Integer
      ival = cl2.Value
      Dim res As String
      res = Application.WorksheetFunction.Substitute(cl1.Text, "?", Trim(Str(ival)))
      cl1 = res
    Next cl1
End Sub
Sub test()
    Dim rng As Range, cl As Range
    Set rng = Range("A1:A4")
    Dim cl1 As Range, cl2 As Range
    For Each cl1 In rng
      Set cl2 = cl1.Offset(0, 1)
      Dim ival As Integer
      ival = cl2.Value
      cl1.Replace What:="~?", Replacement:=Str(ival)
    Next cl1
End Sub

macro to move data from one column to another, by detecting space character in a word of the column


By : user3605767
Date : March 29 2020, 07:55 AM
wish of those help In order to determine that the 2nd character of a string is a space, use this:
code :
Dim TheString as String
TheString = "6 ducks"
If Mid(TheString, 2, 1) = " " Then
  MsgBox "There's a space in position 2 of the string"
End If
If IsNumber(Left(MySheet.Range("G" & SomeRow), 1) Then
  MySheet.Range("H" & SomeRow) = MySheet.Range("G" & SomeRow)
  MySheet.Range("G" & SomeRow) = ""
End If

Move last character of each line to new column


By : 陈维榜
Date : March 29 2020, 07:55 AM
wish of those help Which sed/awk command can I use to cut the last number (and remove delimiter _) of each string in column 1 and move it to a new column (column 3)?
code :
$ sed -E 's/(.*)_([0-9]+)(.*)/\1\3 \2/' file
HLA:HLA00001_A*01:01:01:01  1 3503
HLA:HLA02169_A*01:01:01:02N 1 3291
HLA:HLA14798_A*01:01:01:03  1 2903
$ sed 's/\(.*\)_\([0-9]*\)\(.*\)/\1\3 \2/' file
HLA:HLA00001_A*01:01:01:01  1 3503
HLA:HLA02169_A*01:01:01:02N 1 3291
HLA:HLA14798_A*01:01:01:03  1 2903

Is there any way in Python to extract last 2 character from my string column and convert it to numeric column?


By : user3167135
Date : March 29 2020, 07:55 AM
Hope this helps , You can use the astype method.
code :
df1['QUARTER_COLUMN'].str[-2:].astype(int)
df1['year'] = df1['QUARTER_COLUMN'].str[-2:].astype(int)

Numeric column is coerced to character column when another character column is modified


By : Rama Chandran Raju
Date : March 29 2020, 07:55 AM
this one helps. I found my error: df[df$char == "a", ] <- "c" overwrites the whole row, which is why the first column is coerced. The correct way to replace "a" by "c" is: df$char[df$char == "a"] <- "c".
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