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Why is my java code throwing an error when I get input from the user?

By : akira onawa
Date : September 16 2020, 11:00 PM
fixed the issue. Will look into that further I am trying to simply get input from the user, in a method that returns Object. For some reason, this error is thrown: , This question has been asked before.
code :
Scanner scanner = new Scanner(System.in);
String input = null;
if (scanner.hasNextLine()

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My sql Input output stored procedure throwing error while calling from php code

By : Gordon
Date : March 29 2020, 07:55 AM
I hope this helps you . I have made the changes on SP and remove output parameter and then call it from PHP code now its working fine.Below changes I made in SP:
code :

    CREATE DEFINER="root"@"localhost" PROCEDURE "GetModelnBrandCodeFromName"(

    _BrandName nvarchar(100),
    -- out _BrandCode int ,
    _ModelName nvarchar(100)
    -- out _ModelCode int


    -- Declare variables to store result set during query execution :

    declare temp_IntBrandC int;
    declare temp_IntModelC varchar(100);

    Set temp_IntBrandC= (Select CompanyCode From MasterMobileBrand where CompanyName =_BrandName);

      -- select @IntBrandc;

    -- If not, then check if it matches the user agent name
    -- that is usually passed in HTTP headers 
    -- For e.g. when Blackberry is the company name the User Agent name
    -- is RIM 
    IF (temp_IntBrandC is NULL) then

     -- select IntBrandC;
        Set temp_IntBrandC = (Select CompanyCode From MasterMobileBrand where UserAgentName =_BrandName);

        -- print @Intbrandc
    end if;
    IF (temp_IntBrandC is not NULL) then
    -- select @IntBrandC;
        -- SET _BrandCode = temp_IntBrandC ;
        -- select _brandcode;

    -- select Brandcode from mobilemodel where brandcode=temp_IntBrandC limit 1;
        -- Print @brandcode
        SET temp_IntModelC = (select  ModelCode from MobileModel where BrandCode = temp_IntBrandC and ModelName like CONCAT('%',_ModelName,'%') limit 1);
          -- select @IntModelc;
        -- Insert if Model Code does not exist in database
        If(temp_IntModelC is NULL) then
    -- select "hello";
     set @maxmobcode=(Select (MAX(ModelCode) + 1) From MobileModel);
            Insert Into MobileModel(companyname, ModelCode, BrandCode, ModelName, ImageName, IsJavaPhone)
            Values(_BrandName,@maxmobcode, temp_IntBrandC, _ModelName, NULL, False);
            -- get newly inserted ModelCode
            SET temp_IntModelC = (select  ModelCode from MobileModel where BrandCode = temp_IntBrandC and ModelName like   CONCAT('%',_ModelName,'%') limit 1);

    -- Print @IntModelc
        end if;
        If(temp_IntModelC is not NULL) then
            -- SET _ModelCode = temp_IntModelC;

    select Brandcode,Modelcode from mobilemodel where modelcode=temp_IntModelC limit 1;
            -- select _brandcode;
        -- Print @Modelcode
            -- SET _ModelCode = -1;
    set temp_IntModelC=-1;
    select temp_IntModelC as ModelCode;
    end if;
        -- SET _BrandCode = -1;
        -- SET _ModelCode = -1;
        -- select _brandcode,_ModelCode;
    set temp_IntBrandC=-1;
    set temp_IntModelC=-1;
    select temp_IntBrandC as Brandcode,temp_IntModelC as Modelcode;
         -- print @brandcode
        -- print @modelcode
    end if;

public function get_brand_code_nd_model($phonemake,$Format,$phonemodule)

    $query = $db1->query("Call GetModelnBrandCodeFromName('$phonemake','$phonemodule')");

            if($query->num_rows() == 0)
                    header('HTTP/1.1 404 Content not found');
                    //echo "Hi";

                    //log_message('error','Content not found',TRUE);

                if($Format=='json' || $Format=='JSON' || empty($Format))

                        //echo "hi";
                        return json_encode($query->result_array());

                    if($Format=='xml' || $Format=='XML')


                        foreach ($query->result_array() as $value)

                                $xml = Xml_writer::createXML('activation', $value);
                                echo $xml->saveXML();

In the java programming, if the input validation fails, how can I allow user to retry three times before throwing an exc

By : user3793801
Date : March 29 2020, 07:55 AM
like below fixes the issue Use loop in which
read and validate input from user. if validation will work fine exit loop if validation will fail increase tries counter if tries counter will be greater than predefined max throw runtime exception with your message.

Liferay Input Edtior throwing error (__ckeditor.java : 827)

By : Iliya Yordanov
Date : March 29 2020, 07:55 AM
To fix the issue you can do Adding in configuration.jsp solved the issue.

How can I prevent my Java code from processing if there is a user-input error?

By : user2657394
Date : March 29 2020, 07:55 AM
To fix this issue I am writing a temperature converter that uses a gui. I have it set up to if the user inputs a string or an invalid temperature, an error label appears under the input box. However, the code will still process as if the user inputted a 0. It will still output the conversions. How can I stop it from doing that in the class I have below? , return a null value from catch block e.g
code :
 public double getDoubleValue()
        double returnValue = 0;
        lblMessage.setText(" ");

            returnValue =   Double.parseDouble(txtInput.getText());

        catch (NumberFormatException nfex)
            return null;
        return returnValue;

User Input Error, no throwing Exceptions or using try{}catch{}

By : Joe
Date : March 29 2020, 07:55 AM
wish helps you I'm trying to create a method that uses a while loop that includes a look ahead method to handle wrong user input: input out of 1-10 range or input a string. I am trying to do this with out throwing exceptions or using try{}catch{}; if possible. I haven't found a post that does not use these and all my attempts have failed so far. A basic idea will work. , There's an error:
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