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Why is the function to find factorial wrong?


Why is the function to find factorial wrong?

By : Raja Mani
Date : September 23 2020, 04:00 AM
I wish this helpful for you In line 5, you overwrite the requested value of n with 0.
That then evaluates to zero (false), and the next two conditionals are also rendered false, so nothing prints.
code :


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i want to find the factorial of a given number using recursive function in c.what's wrong with the following program?

i want to find the factorial of a given number using recursive function in c.what's wrong with the following program?


By : Arvind Balgo
Date : March 29 2020, 07:55 AM
wish help you to fix your issue You do not have a base condition in the fact function.
You need to check:
code :
 if(i == 1){
    return 1;
 }else{

   return i * fact(i - 1);

}
What's wrong with this factorial function in clojure

What's wrong with this factorial function in clojure


By : mohammed Huner
Date : March 29 2020, 07:55 AM
wish help you to fix your issue You can't recur on let.
When you recur here, you are actually recurring on the function definition which has one argument hence java.lang.IllegalArgumentException: Mismatched argument count to recur, expected: 1 args, got: 2 (NO_SOURCE_FILE:33).
Why this factorial function gives wrong result?

Why this factorial function gives wrong result?


By : Dwitty
Date : March 29 2020, 07:55 AM
hope this fix your issue
code :
def Factorial(n):
   result = 1
   for i in range(1,n):
        result = result * (i+1)
   print(result)
result = result * (result+1)
result = result * (i + 1)
What is wrong with my Factorial Function logic?

What is wrong with my Factorial Function logic?


By : Luc Ghesquiere
Date : March 29 2020, 07:55 AM
With these it helps Where you said var newX = x * i;, that declares a new variable. Remove var.
x * i will return the square of x because lastly i is x.
code :
function factorial(x) {
    var newX = 1;
    if(x > 0){
        for(var i = 1;i <= x;i++){
            newX = newX * i;
        }
        return newX;
    } else {
        return 1;
    }
};
console.log(factorial(5));
console.log(factorial(4));
console.log(factorial(0));
Haskell: What is wrong with factorial function

Haskell: What is wrong with factorial function


By : Annie Churdar
Date : March 29 2020, 07:55 AM
may help you . This is ghc being conservative. Your code has all possible values of "n" covered, but ghc isn't smart enough to prove that, so it warns you.
Try replacing your "n < 0" with "otherwise" and putting it at the end. This is defined as
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