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Output of the for loop?


Output of the for loop?

By : panida.w
Date : September 23 2020, 05:00 PM
it should still fix some issue , There is one occurrence of
code :
 count++;
int main() {
      int i,j,count;
      count=0;
      for(i=0; i<5; i++);  
     {                       // i == 5, count == 0
        for(j=0;j<5;j++);    
            {                // i == 5, j == 5, count == 0
                count++;     // i == 5, j == 5, count == 1
            }
      }
      printf("%d",count);     //i == 5, j == 5, count == 1
      return 0;
     }
int main(void) {
      int i,j,count;
      count=0;
      for(i=0; i<5; i++)   // ; removed
      {
         // no code
      }
      {                         // just another block, not previous loop body 
      for(j=0;j<5;j++)    // ; removed
      {
         // again no code
      }
      {                         // again just another block, not previous loop body 
          count++;
      }
      }
      printf("%d",count);
      return 0;
     }
int main() {
      int count = 0;

      {
         count++;
      }

      printf("%d",count);
      return 0;
     }


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How to loop an awk command on every column of a table and output to a single output file?

How to loop an awk command on every column of a table and output to a single output file?


By : karishma shaik
Date : March 29 2020, 07:55 AM
wish of those help awk tells you how many fields are in a given row in the variable NF, so you can create two arrays to keep track of the information you need. One array will keep the value of the last row in the given column. The other will count the number of switches in a given column. You'll also keep a track of the maximum number of columns (and set the counts for new columns to zero so that they are printed appropriately in the output at the end if the number of switches is 0 for that column). You'll also make sure you don't count the transition from an empty string to a non-empty string — which happens when the column is encountered for the first time.
If, in fact, the file is uniformly the same number of columns, that will only affect the first row of data. If subsequent rows actually have more columns than the first line, then it adds them. If a column stops appearing for a bit, I've assumed it should resume where it left off (as if the missing columns were the same value as before). You can decide on different algorithms; that could count as two transitions (from number to blank and from blank to number too. If that's the case, you have to modify the counting code. Or, perhaps more sensibly, you could decide that irregular numbers of columns are simply not allowed, in which case you can bail out early if the number of columns in the current row is not the same as in the previous row (beware blank lines, or are they outlawed too?).
code :
awk '{   if (NF > maxNF)
         {
             for (i = maxNF + 1; i <= NF; i++)
                 count[i] = 0;
             maxNF = NF;
         }
         for (i = 1; i <= NF; i++)
         {
             if (col[i] != "" && $i != col[i])
                 count[i]++;
             col[i] = $i;
         }
     }
     END {
         for (i = 1; i <= maxNF; i++)
             print count[i];
     }' data-file-with-4000-columns
3
0
3
0
5
1 2 3 1 2
1 2 2 1 3
1 2 3 1 2
2 2 2 1 2
2 2 2 1 2 1 1 1
3 2 2 1 2 2 1
3 2 2 1 1
1 2 2 1 1 2 2 1
1 2 2 1
1 2 2 1 1 3
3
0
3
0
3
2
1
0
Powershell & Lotus Notes - change output of While Loop from Text to XML Output

Powershell & Lotus Notes - change output of While Loop from Text to XML Output


By : Narayan
Date : March 29 2020, 07:55 AM
wish of those help I am running a Powershell script against a view on a Lotus Notes server. It currently produces output in the manner that follows: , The following line deals with the record output.
code :
$zOut = $userID + $delim + $name + $delim +  $internetAddress 
$zOut = "<UserID>" + $userID + "</UserID>" ..... (etc)
Incorrect output from text-replace loop, unexpected duplicated output

Incorrect output from text-replace loop, unexpected duplicated output


By : sunmashelly
Date : March 29 2020, 07:55 AM
hope this fix your issue The problem is your modifying the text inside your loop, a separate output should be created rather than an in-place replace.
Don't even bother doing it like that, use a Regex.Replace callback function.
code :
using System.IO;
using System;
using System.Collections;
using System.Text.RegularExpressions;


class Program
{
    static void Main()
    {

        string Plainttext = "This selection is automatically generated based on videos that were popular <br/>" +
" in the past few weeks. <br/>" +
" ------------------------------------------------------------------- \n" +
" 'Anniversary Prank Backfires!! \n" +
" http://www.youtube.com/watch?v=R7AXBOT8KzU&feature=em-hot \n" +
" by RomanAtwood " +
" 23,268,129 views " +
" ------------------------------------------------------------------- \n" +
" We Are The World for Philippines [TYPHOON HAIYAN] \n" +
" http://www.youtube.com/watch?v=1bI8pGLBagY&feature=em-hot \n" +
" by Kevin Ayson " +
" 3,607,584 views <br/>" +
" ------------------------------------------------------------------- <br/>" +
" end of text ";

        MatchEvaluator evaluator = new MatchEvaluator(MatchFilter);

        Console.WriteLine(Regex.Replace(Plainttext, 
        "youtu(?:\\.be|be\\.com)/(?:.*v(?:/|=)|(?:.*/)?)([a-zA-Z0-9-_]+)", evaluator, 
                                      RegexOptions.IgnorePatternWhitespace));  
    }

    static string MatchFilter(Match match) {
        var id = match.Groups[1].Value;
        var geturl = match.ToString();
        return  string.Format(@"<table  runat ='server'><tr> <td id = 'tduserPicture' 
                    rowspan='1' style='text-align:left'  runat='server'>
                  <img ID='Imagess2' runat='server' src='{0}' Height='80px' Width='100px'  /alt='image'> 
              <br/> {1} </td> </tr></table>", "http://img.youtube.com/vi/" + id + "/0.jpg", "www." + geturl);
    }
}
This selection is automatically generated based on videos that were popular <br/> in the past few weeks. <br/> ------------------------------------------------------------------- 
 'Anniversary Prank Backfires!! 
 http://www.<table  runat ='server'><tr> <td id = 'tduserPicture' 
                    rowspan='1' style='text-align:left'  runat='server'>
                  <img ID='Imagess2' runat='server' src='http://img.youtube.com/vi/R7AXBOT8KzU/0.jpg' Height='80px' Width='100px'  /alt='image'> 
              <br/> www.youtube.com/watch?v=R7AXBOT8KzU </td> </tr></table>&feature=em-hot 
 by RomanAtwood  23,268,129 views  ------------------------------------------------------------------- 
 We Are The World for Philippines [TYPHOON HAIYAN] 
 http://www.<table  runat ='server'><tr> <td id = 'tduserPicture' 
                    rowspan='1' style='text-align:left'  runat='server'>
                  <img ID='Imagess2' runat='server' src='http://img.youtube.com/vi/1bI8pGLBagY/0.jpg' Height='80px' Width='100px'  /alt='image'> 
              <br/> www.youtube.com/watch?v=1bI8pGLBagY </td> </tr></table>&feature=em-hot 
 by Kevin Ayson  3,607,584 views <br/> ------------------------------------------------------------------- <br/> end of text 
In R Studio, how can I stop my for-loop from overwriting stored output with the most recent output?

In R Studio, how can I stop my for-loop from overwriting stored output with the most recent output?


By : user2651563
Date : March 29 2020, 07:55 AM
will help you I've build a for-loop that should store the first and surname of a soccer player (scraped from a website) in separate columns, but the for-loop keeps overwriting all stored results with the most recent output.
code :
for(i in seq_along(playeridtest)) { # Note change here
  scoresway <- paste("http://www.scoresway.com?sport=soccer&page=person&id=",playeridtest[i], sep="")
  scoresway <- read_html(scoresway)
  urlnodescorefirst <- html_node(scoresway, "dd:nth-child(2)")
  urltextscorefirst <- html_text(urlnodescorefirst)
  playernames$first[i] <- urltextscorefirst
  urlnodescoresur <- html_node(scoresway, "dd:nth-child(4)")
  urltextscoresur <- html_text(urlnodescoresur)
  playernames$sur[i] <- urltextscoresur
}
playernames
  playernames id   first          sur
1          NA  4 Maarten Stekelenburg
2          NA 11  Robert         Huth
3          NA 14 Philipp         Lahm
# playernames <- rep(NA, noplayers) 
# playernames <- as.data.frame(playernames)
playernames<-NULL
In the below program I was expected Infinite loop as a output. But output is 0, please help me with explain the concept

In the below program I was expected Infinite loop as a output. But output is 0, please help me with explain the concept


By : ayan
Date : March 29 2020, 07:55 AM
To fix this issue i is uninitialized. It can have any value. If it has a value greater/equal than 30, the loop will not execute and s remains 0.
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