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Why C programming gives different output?


Why C programming gives different output?

By : Renga
Date : September 24 2020, 03:00 AM
wish help you to fix your issue In C, putting either 0x or 0 before an integer literal value will cause the compiler to interpret the number in base 16 (hexadecimal) and base 8 (octal), respectively.
Normally, we interpret and read numbers in base 10 (decimal). However, we sometimes will use these other bases because they are useful powers of 2 that can represent groups of bits (1 hexadecimal digit = 4 bits, 1 octal digit = 3 bits), and bit manipulation is something that C wants to provide. This is why you'll see something like char be represented with 2 hexadecimal digits (e.g. 0x12) to set a single char to be a specific bit sequence.
code :
#include <stdio.h>
int main()
{
    int a = 0100;
    int b = 010;
    int c = 1111;
    int d = 01111;
    printf("0100 => %o, 010 => %o, 1111 => %d, 01111=> %o\n", a,b,c,d);
}
gcc -ansi -O2 -Wall main.c && ./a.out
0100 => 100, 010 => 10, 1111 => 1111, 01111=> 1111


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What is the output? C Programming

What is the output? C Programming


By : Dherio Dewa R
Date : March 29 2020, 07:55 AM
This might help you You are correct: !a giver you 0 and 0 == b is 0,
So, c = ++b gives b = 4 and c = 4. The a is not changed.
C programming nan output

C programming nan output


By : Marty
Date : March 29 2020, 07:55 AM
With these it helps You have fallen victim to garbage values - a common mistake for beginners. Specifically, its happening in these lines -
code :
float total;
float low;
float high;
float average;
float total=0;
float low;
float high;
float average=0;
printf("\n\nPlease enter a positive number to continue or a negative number");
printf(" to stop: ");

scanf("%f", &input);
low=input;
high=input;

while (input > 0)
....
....
Why this C programming code output is False? expected output is true

Why this C programming code output is False? expected output is true


By : user3293475
Date : March 29 2020, 07:55 AM
seems to work fine Operator sizeof returns a value of some unsigned integral type that has typedef name size_t. For example it can be unsigned long But in any case the rank of size_t is not less than the rank of int.
According to the rules of usual aruthmetic conversions (the C Standard, 6.3.1.8 Usual arithmetic conversions)
code :
if (sizeof(int) > -1)
if (sizeof(int) > SIZE_MAX)
if (sizeof(int) > -1ll)
#include <stdio.h>

int main(void) 
{
    if ( sizeof( int ) > -1 )
    {
        puts( "True" );
    }       
    else
    {
        puts( "False" );
    }

    if ( sizeof( int ) > -1ll )
    {
        puts( "True" );
    }       
    else
    {
        puts( "False" );
    }

    return 0;
}
False
True
How to get the following output in C programming

How to get the following output in C programming


By : nobita lee
Date : March 29 2020, 07:55 AM
I wish this helpful for you You do not need to give control to else twice. All you need is a false condition with a side effect of printing the other "Hello", for example
DIfference in output of srand() on windows gcc and expected output for C programming?

DIfference in output of srand() on windows gcc and expected output for C programming?


By : mgarbaz
Date : March 29 2020, 07:55 AM
I wish this help you i would like to know why there is a difference in the output from my gcc compiler in Sublime Text 3 on Windows 10 and the expected output? If so how can i change the compiler such that it operates the same? , From C11 standard:
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