How to get float value from uint32_t?

How to get float value from uint32_t?

By : Bryan Raynolds
Date : September 24 2020, 03:00 AM
seems to work fine i use this part of code to read float value from OSC message on my microcontroller. However i get "dereferencing type-punned pointer will break strict-aliasing rules [-Wstrict-aliasing]" error and no value is showed on printf. Is there any workaround for this one? marker is in struct as:
code :
float tosc_getNextFloat(tosc_message *o) {
  // convert from big-endian (network btye order)
  const uint32_t i = ntohl(*((uint32_t *) o->marker));
  o->marker += 4;

  float tmp = 0;
  memcpy((void *)&tmp, (void *)&i, sizeof(uint32_t));
  return tmp;

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UINT_MAX->float->uint32_t Results in 0 on VC++

UINT_MAX->float->uint32_t Results in 0 on VC++

By : Xannisth
Date : March 29 2020, 07:55 AM
seems to work fine When converting from an integer type to a real type the result may be inexact and rounded towards the closest representable (above or below the original value) in the real type. In your case float has 24 bits in its mantissa part, so, 0xFFFFFFFF isn't going to survive the conversion unchanged as it needs 32 bits of mantissa. So, it can convert to 0x100000000 (closest above). If that happens, you'll be converting 0x100000000 from float to your 32-bit unsigned type. And this conversion results in undefined behavior (which includes unpredictable/unreliable results) because the value is outside of the range of the 32-bit unsigned type.
You also get UB with the other compiler, you're just unaware of it. Circumvent optimization by introducing volaitle (in declarations of r1, r2 and r3) and you'll see it (ideone.com/1CCat8).
Copy bit pattern: float to uint32_t

Copy bit pattern: float to uint32_t

By : Madhav Hatwalne
Date : March 29 2020, 07:55 AM
it should still fix some issue Yes, this is undefined behaviour as it breaks the strict aliasing rule:
Store float value in uint32_t pointer

Store float value in uint32_t pointer

By : I Is Uh Ninja
Date : March 29 2020, 07:55 AM
will help you The simplest approach to reinterpret the bits would be to use memcpy, if you know that sizeof(float) == sizeof(uint32_t) 1
code :
float f = /* some_val */;
uint32_t fbits = 0;
memcpy(&fbits, &f, sizeof fbits);
union {
  float    from;
  uint32_t to;
} pun = { .from = /*some val*/ };

// use pun.to
Conversion to float in uint32_t calculation

Conversion to float in uint32_t calculation

By : Maksim L
Date : March 29 2020, 07:55 AM
this will help I am trying to improve a SWRTC by modifying the definition of a second (long unsigned n_ticks_per_second) by synchronizing time with a server. , This line
code :
drift_per_sec_TICK = total_drift_SEC / (at_update_posix_time - last_update_posix_time);
drift_per_sec_TICK = (float) total_drift_SEC / (at_update_posix_time - last_update_posix_time);
bitwise casting uint32_t to float in C/C++

bitwise casting uint32_t to float in C/C++

Date : March 29 2020, 07:55 AM
To fix the issue you can do I'm receiving a buffer from a network which was converted to an array of 32-bit words. I have one word which is defined as an ieee float by my interface document. I need to extract this word from the buffer. It's tough to cast from one type to another without invoking a conversion. The bits are already adhere to the ieee float standard, I don't want to re-arrange any bits. , In C++, the right way™ is:
code :
float ieee_float(uint32_t f)
    static_assert(sizeof(float) == sizeof f, "`float` has a weird size.");
    float ret;
    std::memcpy(&ret, &f, sizeof(float));
    return ret;
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