How can I wait for form2 to finish?

How can I wait for form2 to finish?

By : dcollier
Date : September 29 2020, 06:00 AM
this will help I have a WinForms app that needs input from the user in Form2. The app needs to wait for form2 to close. What code would I need to use in order for Form1 to wait for the other form to close? , There are two ways to open another form
code :
var  frm = new MyForm();
var frm = new MyForm();
var frm = new MyForm();
if (frm.ShowDialog(this) == DialogResult.OK) {
    // OK button pressed
} else {
    // Cancel button pressed

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wait command wont wait for child process to finish c cpp c++

wait command wont wait for child process to finish c cpp c++

By : Ken Katsu
Date : March 29 2020, 07:55 AM
To fix the issue you can do I see four problems:
1) execlp() is failing: execlp() (or any of the exec family of functions) completely replaces the currently running process image if successful - it is not expected to return, unless something goes wrong. But you are seeing the "Child: Done sleeping, returning" message, so it cannot have succeeded. (In your example, I would guess that this is probably because dmegs should have been dmesg.)
code :
#include <string.h>
#include <unistd.h>
#include <stdio.h>
#include <sys/types.h>
#include <sys/wait.h>

int main(void)
        pid_t pid;
        int pfd[2];
        if(pipe(pfd) == -1)
                perror("error on pipe call");

        pid = fork();
        if(pid == 0){//child process
                fprintf(stderr, "Child: My PID = %d\n", getpid());
                fprintf(stderr, "Child: Running...\n");
                close(pfd[0]); //close read end of pipe
                dup2(pfd[1],1);//connect the pipes
                close(pfd[1]);//close extra file descriptors
                fprintf(stderr, "child starting command: sleep 5\n");
                execlp("sleep", "sleep", "5", (char *)0);//Load the program
                fprintf(stderr, "child: execlp failed\n");
                fprintf(stderr,"Parent: My PID = %d\n", getpid());
                fprintf(stderr,"Parent: Running...\n");
                close(pfd[1]); //close the write end of the pipe
                dup2(pfd[0],0);//connect the pipes
                close(pfd[0]); //close extra file descriptor
                fprintf(stderr,"parent starting command: cat\n");
                execlp("cat", "cat", (char *)0);//Load the programm
        fprintf(stderr,"all done\n");
        return 0;
$ gcc -Wall -o wait wait.c
$ ./wait
Child: My PID = 27846
Child: Running...
child starting command: sleep 5
Parent: My PID = 27845
Parent: Running...
parent starting command: cat
Grand Central Dispatch. How to run one async group, wait, then run another, wait again, then finish?

Grand Central Dispatch. How to run one async group, wait, then run another, wait again, then finish?

By : user3867437
Date : March 29 2020, 07:55 AM
Any of those help There are lots of different ways to do this, but the most conceptually simple (or at least obvious) way would be to create a group for each stage of your "pipeline", then have the completion callback for group A schedule the work on group B which also has a completion callback which schedules the work on group C.
The key here is not to actually "wait" for a group to complete - that's unnecessary. Groups can have completion blocks that will get run automatically when the last block in that group finishes (see dispatch_group_notify()), and this is a good way of creating "fan in" points where you've fanned out a bunch of work in the group.
Does Selenium implicit wait always take the entire wait time or can it finish sooner?

Does Selenium implicit wait always take the entire wait time or can it finish sooner?

By : user2990070
Date : March 29 2020, 07:55 AM
I wish this helpful for you It can finish once it was able to find the element. If not it does throws the error and stops. The poll time is again very specific to the driver implementation ( not Java bindings , but the driver part, example: FireFox extension, Safari Extension etc.)
As I have mentioned here, these are very specific to the driver implementation. All driver related calls goes via execute method.
code :
protected Response execute(String driverCommand, Map<String, ?> parameters) {
    Command command = new Command(sessionId, driverCommand, parameters);
    Response response;

    long start = System.currentTimeMillis();
    String currentName = Thread.currentThread().getName();
        String.format("Forwarding %s on session %s to remote", driverCommand, sessionId));
    try {
      log(sessionId, command.getName(), command, When.BEFORE);
      response = executor.execute(command);
      log(sessionId, command.getName(), command, When.AFTER);

      if (response == null) {
        return null;
      //other codes 
response = executor.execute(command);
Wait for busboy on#file to finish before calling on#finish

Wait for busboy on#file to finish before calling on#finish

By : Bes Eiredt
Date : March 29 2020, 07:55 AM
To fix this issue So okay I have this: , You have a function and variables like this
code :
var finishOne, FinishTwo

finish(finish1, finish2) {
     if (finishOne != true && finish1 != null) finishOne = finish1;
     if (finishTwo != true && finish2 != null) finishTwo = finish2;
     if (finishOne && FinishTwo) {
         //RUN CODE
finish(true, null) And the other one with finish(null, true)
Fork(), wait for all child process to finish vs wait for one child to finish

Fork(), wait for all child process to finish vs wait for one child to finish

By : stolenmoment
Date : March 29 2020, 07:55 AM
this will help I don't understand as to where should I use the wait(NULL) or while(pid = wait(&status))>0). I am very confused and I get weird results please help!. , The same modification can do both jobs.
code :
#include <stdio.h>
#include <stdlib.h>
#include <sys/wait.h>
#include <unistd.h>

int main (int argc, char *argv[])
    pid_t childpid = 0; 
    int i, n;

    if (argc != 2)
    {   /* check for valid number of command-line arguments */ 
        fprintf(stderr, "Usage: %s processes\n", argv[0]);
        return 1; 
    n = atoi(argv[1]);  
    for (i = 1; i < n; i++)
        if ((childpid = fork()) <= 0)

    int corpse;
    int status;

    while ((corpse = wait(&status)) > 0)
        fprintf(stderr, "%d: child %d exited with status 0x%.4X\n",
               (int)getpid(), corpse, status);

    fprintf(stderr, "i:%d  process ID:%ld  parent ID:%ld  child ID:%ld\n",
            i, (long)getpid(), (long)getppid(), (long)childpid);
    return 0; 
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