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How to Deserialize a JSON into a list using SIMPLE JSON?


By : Ethilyk
Date : September 29 2020, 08:00 AM
I wish this help you The simplest way to deserialize json is often to create classes which model your json object. You can use json2csharp to create the classes, or use Visual Studio (Edit -> Paste Special -> Paste JSON as Classes).
Create the classes below then you can use JsonConvert to deserialize the json into your object. Note that since you're only interested in SaveValues you don't need to map other properties (like NoteValues).
code :
var myModel = JsonConvert.DeserializeJson<List<Response>>(json);

// access by iterating through properties
foreach (var item in response)
{
    foreach (var saveValue in item.SaveValues)
    {
        // get all properties of saveValue...
        // saveValue.Allposition;
        // saveValue.Allrotation;
        // saveValue.Allscale;
        // ....
    }
}
public class Allposition
{
    public double x { get; set; }
    public double y { get; set; }
}

public class Allrotation
{
    public double x { get; set; }
    public double y { get; set; }
    public double z { get; set; }
    public double w { get; set; }
}

public class Allscale
{
    public double x { get; set; }
    public double y { get; set; }
}

public class Linepos0
{
    public double x { get; set; }
    public double y { get; set; }
    public double z { get; set; }
}

public class Linepos1
{
    public double x { get; set; }
    public double y { get; set; }
    public double z { get; set; }
}

public class SaveValue
{
    public int Id { get; set; }
    public Allposition Allposition { get; set; }
    public Allrotation Allrotation { get; set; }
    public Allscale Allscale { get; set; }
    public Linepos0 Linepos0 { get; set; }
    public Linepos1 Linepos1 { get; set; }
    public int Movetype { get; set; }
}

public class Response
{
    public List<SaveValue> SaveValues { get; set; }
    // NoteValues can safely be removed from model if you don't need the values
    public List<NoteValue> NoteValues { get; set; }
}

// optional
public class NoteValue
{
    public int Movenumber { get; set; }
    public string Notemsg { get; set; }
}


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<CLOSED(Reason: JSON String Error)>Unable to Deserialize List<myObject> from Valid JSON


By : Anthony Sager
Date : March 29 2020, 07:55 AM
I wish this helpful for you I am trying to de-serialize a JSON string to a List of objects. The json string is a valid json as verified from http://jsonlint.com/ , It works for me:
code :
public class Employee
{
    public int Employee_OID { get; set; }
    public string First_Name { get; set; }
    public string Last_Name { get; set; }
}

class Program
{
    static void Main(string[] args)
    {
        string json = @"[{""Employee_OID"": 18450,""First_Name"": ""ABDUL"",""Last_Name"": ""RAJPUT""},{""Employee_OID"": 22446,""First_Name"": ""ABDUL"",""Last_Name"": ""KHAN""}]";
        List<Employee> emp = (new JavaScriptSerializer()).Deserialize<List<Employee>>(json);
        Console.WriteLine(emp.First().First_Name);
    }
}

Very simple attempt to deserialize JSON with JSON.NET does not work


By : JennyR
Date : March 29 2020, 07:55 AM
will help you Your JSON has more than one object, and neither are in an array. You either need to remove one of the objects from the JSON or add them to an array and deserialize them properly:
code :
string responseBody = 
    @"[
        {""HighScoreId"":1,""Name"":""Debra Garcia"",""Score"":2.23},
        {""HighScoreId"":2,""Name"":""Thorsten Weinrich"",""Score"":2.65}
    ]";

var highScores = 
    JsonConvert.DeserializeObject<List<GlobalHighScore>>(responseBody);

How to deserialize JSON objects to List<> when the items are not in a Json array? (C#)


By : Jedii
Date : March 29 2020, 07:55 AM
wish of those help I'm using a Json string from another system. It looks something like this: , If I'm understanding correctly, you'll need a class setup like this:
code :
public class Results {
    public bool BoolValue { get; set; }
    public Dictionary<string, Item> Inventory { get; set; }
}

public class Item {
    public string id { get; set; }
    public string name { get; set; }
}

Jackson: Deserialize JSON array from JSON object into Java List


By : user3290644
Date : March 29 2020, 07:55 AM
To fix this issue I have been stumbled by this for a while. I have a Spring application and would like to parse the following JSON: , you can define your json structure with a couple of classes
code :
public class MyJson {
  private MyResponse response;
  ...
}

public class MyResponse {
  private List<MyClass> objects;
  ...
}

public class MyClass {
  String name;
  List<CustomProperty> customProperties;
  ...
}
ObjectMapper objectMapper = new ObjectMapper();
MyJson myJson = objectMapper.readValue(json, MyJson.class);
List<MyClass> list =  myJson.getResponse().getObjects();

How to deserialize a JSON array to a List using System.Runtime.Serialization.Json


By : Franky
Date : March 29 2020, 07:55 AM
With these it helps What I did not take into consideration is that CourseWork is not a list, it just has lists inside it as private member variables. To fix my problem I had to change my List ReadJsonFile1(List obj) function back to what I had it earlier in the project T ReadJsonFile1(T obj) Basically just taking all the Lists out and making them normal type of T. I also needed to add DataContract Names to ALL my classes. My DataMembers were fine but since this is a Json Array I needed to add the DataContract above every class like in the Assignment class and also the CourseWork Class, just need to make sure you give your DataContract the correct name.
SOLUTION
code :
List<T> ReadJsonFile1<T>(List<T> obj)
 [DataContract(Name = "coursename")]
  public class CourseWork
  {
[DataContract(Name = "assignments")]
    public class Assignment
     {
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