Invalid Regex is accepted by Java. Is this a Java bug or a missed interpretation of expectations

Invalid Regex is accepted by Java. Is this a Java bug or a missed interpretation of expectations

By : Catalina Stancu
Date : October 16 2020, 06:10 AM
Any of those help I'd say the links to the regex test tools are wrong (in the PCRE sense of it). I think this is so because of JS implementations handle these matches differently (see: https://github.com/gskinner/regexr/issues/28)
Note that both regexr and regex101 accept ^()* and (^)*. Also, Perl v5.18.2 has no issue with it: running echo "ubar" | perl -ne "s/^*/F/; print;" from my terminal results in no warnings or errors and will print Fubar.
code :

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What is missed signal in java? how calling notify() be missed by the waiting thread?

What is missed signal in java? how calling notify() be missed by the waiting thread?

By : Ofek
Date : March 29 2020, 07:55 AM
To fix this issue Signal can be missed if doNotify called before doWait. So doNotify should mark somehow that it was called. The usual way for this is using a variable. Uncomment all usages of wasSignalled and the signal will not be missed.
Java/Hive regex interpretation

Java/Hive regex interpretation

By : Lucky Singh
Date : March 29 2020, 07:55 AM
hop of those help? Straightforward question, it's just difficult to google regex syntax... , First break apart the regex:
code :
Java regex wildcard not accepted

Java regex wildcard not accepted

By : tossed456
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further [\\s].(?i)[snd] This in your regex ensures that there must a character present inbetween the space and n (followed by zero or more spaces plus ( symbol). But there isn't a character actually. So your regex fails and returns the original string without doing any replacements.
code :
String depends2 = "success(job1) AND n(job2)";
depends2  = depends2.replaceAll("\\s(?i)[snd]\\s*\\(", "");     
success(job1) ANDjob2)
\s                       whitespace (\n, \r, \t, \f, and " ")
(?i)                     set flags for this block (case-
                         insensitive) (with ^ and $ matching
                         normally) (with . not matching \n)
                         (matching whitespace and # normally)
[snd]                    any character of: 's', 'n', 'd'
\s*                      whitespace (\n, \r, \t, \f, and " ") (0 or
                         more times)
\(                       '('
What's the accepted way to write Java methods where return value may be invalid?

What's the accepted way to write Java methods where return value may be invalid?

By : Pavle Pantovic
Date : March 29 2020, 07:55 AM
should help you out I wouldn't even write the method. There's nothing special about the root that you need a specific method to get its value. The entire method is redundant. You need something to get the root, and you need something to get the value out of any node (and its left and right children too).
I would write two methods:
Having difficulty understanding Java regex interpretation

Having difficulty understanding Java regex interpretation

By : user3608292
Date : March 29 2020, 07:55 AM
With these it helps - only indicates a range if it's within a character class (i.e. square brackets []). Otherwise, it's a normal character like any other. With that in mind, this regex matches the following examples:
"-2" "3" "-700" "436"
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