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Recurvisely find children of children and remove


By : Ghis
Date : October 16 2020, 06:10 AM
Hope this helps Here's a functional way you can do it using recursion. The numbered bullet points match the numbered comments in the code below.
(base) There is no node so there is nothing left to process; return the result r (induction) There is at least one node. If the node's id or parentid is in the set s, a matching node has been found. Add the node's id to the set and start the search over with the partial result r and the remaining nodes, more. (induction) There is at least one node and it does not match the ids we are searching for. Append the node to the result and continue searching more nodes.
code :
const removeFamily =
  ( id = 0
  , [ node, ...more ] = []
  , s = new Set ([ id ])
  , r = []
  ) =>
    node === undefined
      ? r                               // 1
      : s .has (node.id) || s .has (node.parentid)
          ? removeFamily                // 2
              ( id
              , [ ...r, ...more ]
              , s .add (node.id)
              , []
              )
          : removeFamily                // 3
              ( id
              , more
              , s
              , [ ...r, node ]
              )

const nodes =
  [ { id: 1, parentid: 0 }
  , { id: 2, parentid: 1 }
  , { id: 3, parentid: 2 }
  , { id: 4, parentid: 2 }
  , { id: 10, parentid: 4 }
  , { id: 5, parentid: 0 }
  , { id: 6, parentid: 5 }
  , { id: 7, parentid: 7 }
  ]

const newNodes =
  removeFamily (1, nodes)

console .log (newNodes)
// [ { id: 5, parentid: 0 }
// , { id: 6, parentid: 5 }
// , { id: 7, parentid: 7 }
// ]
const removeFamily =
  ( id = 0
  , [ node, ...more ] = []
  , s = new Set ([ id ])
  , r = []
  ) =>
  { if (node === undefined)
      return r               // 1
    else if (s .has (node.id) || s .has (node.parentid))
      return removeFamily    // 2
        ( id
        , [ ...r, ...more ]
        , s .add (node.id)
        , []
        )
    else
      return removeFamily    // 3
       ( id
       , more
       , s
       , [ ...r, node ]
       )
  }
const recur = (...values) =>
  ({ recur, values })

const loop = f =>
{ let a = f ()
  while (a && a.recur === recur)
    a = f (...a.values)
  return a
}

const removeFamily = (id = 0, nodes = []) =>
  loop
    ( ( [ node, ...more ] = nodes
      , s = new Set ([ id ])
      , r = [] 
      ) =>
        node === undefined
          ? r                           // 1
          : s .has (node.id) || s .has (node.parentid)
            ? recur                     // 2
                ( [ ...r, ...more ]
                , s .add (node.id)
                , []
                )
            : recur                     // 3
                ( more
                , s
                , [ ...r, node ]
                )
    )

const nodes =
  [ { id: 1, parentid: 0 }
  , { id: 2, parentid: 1 }
  , { id: 3, parentid: 2 }
  , { id: 4, parentid: 2 }
  , { id: 10, parentid: 4 }
  , { id: 5, parentid: 0 }
  , { id: 6, parentid: 5 }
  , { id: 7, parentid: 7 }
  ]


const newNodes =
  removeFamily (1, nodes)

console .log (newNodes)
// [ { id: 5, parentid: 0 }
// , { id: 6, parentid: 5 }
// , { id: 7, parentid: 7 }
// ]


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Why does updating children of a record, remove the connection with its children?


By : Gary Simons
Date : March 29 2020, 07:55 AM
it should still fix some issue The code is correct, except that I just added @DynamicUpdate to avoid updating unmodified fields, and removed a line which was updating the table from another function.

XSLT Remove parent and keep children, rename grandparent, and sort children in a given order


By : Andrey
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , I am not sure if this will entirely suit your needs, but try this alternative template for matching div[@class='y']
code :
<xsl:template match="div[@class='y']" >
  <div class="x">
   <xsl:apply-templates select="*[not(self::div[@class='x'])]|div[@class='x']/*">
     <xsl:sort select="@class" />  
   </xsl:apply-templates>
  </div>
 </xsl:template>

python xml.etree - remove node but keep children (assign children to grandparents)


By : vmitn
Date : March 29 2020, 07:55 AM
I wish did fix the issue. In Python, how do I remove a node but keep its children using xml.etree API? , Remove this line from your program:
code :
        country.remove(country_child)

How to find the direct children (not the children of children) of a div in html using BeautifulSoup?


By : madA.reverse
Date : March 29 2020, 07:55 AM
Any of those help Markup : , You can use findChildren() method for getting children tags .
code :
main_cont = soup.find('div',{'class':'parent-div'}).findChildren('div',recursive=False)
[<div class="child-1"><div class="child-1.1"></div></div>, <div class="child-2"><div class="child-2.1"> </div></div>]

In WPF: Children.Remove or Children.Clear doesn't free objects


By : Victor Stoe
Date : March 29 2020, 07:55 AM
With these it helps Update: I tried this on another, more cleanly installed, machine. I could not reproduce this on that machine. If I find out what offending (VSStudio) component causes this, I will let you know. , Change
public class MyControl : UserControl
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