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How to create a 2Darray from a dictionary?


By : Ron Tam
Date : October 16 2020, 06:10 PM
I hope this helps you . Here's one approach. There are a few discrepancies between your sample input file and expected output, so I've gone ahead and shared a solution making some assumptions.
code :
import pandas as pd
# load your file into a list
l = [l.rstrip('\n').split() for l in open('my_file.txt')]
# [['gr2_1', 'gr2_2', '90%'], ['gr2_1', 'gr2_3', '80%'],...
# Construct a dataframe from it
df = pd.DataFrame(l).add_prefix('col')

    col0    col1  col2
0   gr2_1   gr2_2   90%
1   gr2_1   gr2_3   80%
2   gr2_1   gr4_7   55%
3   gr2_2  gr3A_1    5%
4   gr2_2  gr3A_2  100%
5  gr3B_1   gr2_1   60%
(pd.crosstab(index=df.col0, 
            columns=df.col1.str.split('_').str[0], 
            values = df.col2, 
            aggfunc= lambda x: x.str.cat(sep=',')))

col1        gr2     gr3A  gr4
col0                         
gr2_1   90%,80%      NaN  55%
gr2_2       NaN  5%,100%  NaN
gr3B_1      60%      NaN  NaN


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C#: Is it possible to position a 2darray in a certain position in another 2darray without iterating through it?


By : Eric322
Date : March 29 2020, 07:55 AM
To fix this issue No you can't (edit: without copying) , I'm sorry. You could mimic this perhaps with the ArraySegement (but you'd have to use a 1D base array. You may also care to read this paper that suggests plain rectangular arrays are relatively slow in C#.

How to create class with 2DArray in Processing? Is bracket notation forced?


By : BitSpectrum
Date : March 29 2020, 07:55 AM
I wish did fix the issue. Put lines like vertArray[0] = new Vertex(50.0, 50.0, 0.0, 1.0); into the constructor.
Or, intialize vertArray in this way:
code :
// create 8 vertexes for cube
private Vertex[] vertArray = new Vertex[8] {
  new Vertex(50.0, 50.0, 0.0, 1.0),
  new Vertex(150.0, 50.0, 0.0, 1.0),
  new Vertex(150.0, 150.0, 0.0, 1.0),
  new Vertex(50.0, 150.0, 0.0, 1.0),
  new Vertex(50.0, 50.0, -100.0, 1.0),
  new Vertex(150.0, 50.0, -100.0, 1.0),
  new Vertex(150.0, 150.0, -100.0, 1.0),
  new Vertex(50.0, 150.0, -100.0, 1.0)
};

How to modify or create a dictionary based on one dictionary querying the values of another dictionary in Python


By : Irwan Abdullah AlMun
Date : March 29 2020, 07:55 AM
I wish this helpful for you I have two dictionaries: Dictionary A has an increasing and unique Item ID as the key and it is associated to an FID value. , try this code:
code :
dict_a = dict({11111: "FID01", 22222: "FID01", 33333:"FID03", 44444: "FID01"} )
dict_b = dict({"FID01": 25, "FID02": 50, "FID03": 75, "FID04": 90})

dict_b_keys = dict_b.keys()

{key: dict_b[value] for (key, value) in dict_a.items() if value in dict_b_keys}

How to create numpy boolean 2darray based on the argmin of another numpy 2darray?


By : user3001806
Date : March 29 2020, 07:55 AM
like below fixes the issue This ought to do it for you, and I believe it is general enough for non-square arrays and for arrays with irregular masks.
code :
data = [[i == j for j in range(a.shape[-1])] for i in a.argmin(axis=1)]
result = np.ma.masked_array(data=data, mask=a.mask)

How to create a 2Darray grid in Python


By : user3724710
Date : March 29 2020, 07:55 AM
should help you out You can insert lists in lists to create a 2D grid, a more convenient way is to use numpy
code :
x = [["X", "X", "X", "X"],["X", "X", "X", "X"],["X", "X", "X", "X"],["X", "X", "X", "X"],["X", "X", "X", "X"],["X", "X", "X", "X"]]
# 2d grid
print(x)

# insert a "O"
x[2][1] = "O"
print(x)

#### with numpy
import numpy as np

x2 = np.full((6,4), "X")
print(x2)

x2[2, 1] = "O"
print(x2)
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