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Return an array of names

By : buggo Ba
Date : October 16 2020, 06:10 PM
Any of those help I am struggling with returning an array of owner names from a given array of dog objects.
code :
let dogs = [ 
{name: 'Beatrice', breed: 'Lurcher', owner: 'Tom'}, 
{name: 'Max', breed: 'Pug', owner: 'Izzi'}, 
{name: 'Poppy', breed: 'Pug', owner: 'Anat'} ];

function getPugOwners(dogs) { 
  return dogs.filter(dog => dog.breed=='Pug').map(dog => dog.owner);


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How can I make JsonResult return an array of arrays (without field names) rather than an array of objects?

By : samuel damanka
Date : March 29 2020, 07:55 AM
I wish did fix the issue. I have an IEnumerable list of date/value pairs that I am returning as a Json list to flot. However, when I call JsonResult(), the result looks like this: , It sounds like you just need to return a string like this:
code :
var builder = new StringBuilder();
foreach (var item in listOfDateTimes)
    builder.AppendFormat("[{0}, {1}], ", item.Key, item.Value);
var result = builder.ToString().TrimEnd(new char[]{',',' '}) + "]";
return result;

Return PHP array variable-names that are inside a parent array?

By : user3114156
Date : March 29 2020, 07:55 AM
Any of those help It is not possible to retrieve the "names" array1, array2, array3 from an array created with array($array1, $array2, $array3). Those variable names are gone.
You can make the array keys the names though:

PHP return array of matching KEY NAMES and there values

By : Gayesha Himali
Date : March 29 2020, 07:55 AM
With these it helps I'm having a terrible time trying to pull out some values out of an array. Here is a slimmed down version of the array. , Edit:
code :
foreach( $properties as $v ) {
 foreach( $v as $k => $m ) {     

  if( strpos($k, 'MEDIA_IMAGE_TEXT_') !== FALSE  ) {        
    $new_array[] = array('PropertyID' => $v['PropertyID'], 'IMAGE'=>$prev, 'IMAGE_TEXT'=>$m );

  if( strpos($k, 'MEDIA_IMAGE_') !== FALSE ) {
    $prev = $m;  //var_dump($prev);


Search an Array containing strings of names, return names with length of X

By : Gaurav
Date : March 29 2020, 07:55 AM
around this issue Seems like you do not search names with a length of 2, but being composed of 2 names.
Select by the number of name parts:
code :
["Jim Bob", "Jim", "Billy Bob"].select { |names| names.split.length == 2 }
#=> ["Jim Bob", "Billy Bob"]
["Jim Bob", "Jim", "Billy Bob"].select { |name| name.count(' ') == 1 }
#=> ["Jim Bob", "Billy Bob"]

How to return ordened array names?

By : Owais Naeem
Date : March 29 2020, 07:55 AM
will help you I have an array I want to sort from low to high, but I want it to return the array names (G, F, H...) instead of just the numbers. How do I do this? , Use a dictionary:
code :
d = dict(A=12.74087388,       
>>> sorted(d, key=d.get)
['G', 'F', 'H', 'C', 'B', 'E', 'A', 'D']
from operator import itemgetter
print(sorted(d.items(), key=itemgetter(1)))
[('G', 10.16505019),
 ('F', 11.51090636),
 ('H', 11.99872655),
 ('C', 12.31249807),
 ('B', 12.48817861),
 ('E', 12.49693343),
 ('A', 12.74087388),
 ('D', 12.95688859)]
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