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Can I use reduce instead of a for loop?

By : Bartosz Urbaniak
Date : October 16 2020, 06:10 PM
it should still fix some issue I have a hashSet with 0 to X numbers and values of high integer numbers. , Note that std::reduce has the caveat
code :

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Preventing a loop within a loop. How to reduce complexity

By : Hoang Nguyen Minh
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , You have 2 arrays. , Based on my comment:
code :
var arrA = [], arrB = [1, 2, 3, 4, 5, 6, 7, 8, 9, 0];

function addToArray(item){
  if(arrA.indexOf(item) === -1){

function removeFromArray(item){
  var index = arrB.indexOf(item);
  if (index > -1) {
    arrB.splice(index, 1);

function applyItems(arrayOfItems){
  arrayOfItems.map(function(item) {

applyItems([0, 5, 3]);

Bison can't solve conflicts shift-reduce and reduce-reduce

By : S.Baek
Date : March 29 2020, 07:55 AM
wish helps you The second conflict is a classic problem with "optional" elements. It's very tempting to write a rule for optional labels as you have done it, but the fact that optional_label could produce nothing forces the parser to try to make a decision before it has enough information.
LR parsers must "reduce" (recognize) a non-terminal before absorbing any further tokens. They can lookahead at the next k tokens (the next 1 token for an LR(1) parser, which is what bison generates), but they can't tentatively use the token and later go back and do the reduction.
code :
statement: basic_statement | compound
basic_statement: unlabeled_statement | declaration unlabeled_statement
formal_parameter    : expression_parameter | function_parameter
expression_parameter: identifier_list IDENTIFIER
function_parameter  : return_options  IDENTIFIER …

Java Stream API -- How to reduce a loop to reduce

By : Ali Abdullah Khan
Date : March 29 2020, 07:55 AM
To fix the issue you can do You could use flatMap instead:
code :
supStream -> supStream.flatMap(supp -> supp.get().stream());

Solving reduce/reduce and shift/reduce conflicts in bison grammar

By : Nicole
Date : March 29 2020, 07:55 AM
Hope that helps This response is to your UPDATE section, since that's kind of the heart of the problem.
The TL;DR answer is that the precedence-and-associativity declarations %left '+' and %left '*' apply while parsing BINOP but not while parsing expr, so they're too early (they do nothing at this point) and are gone by the time they are needed.
code :
$ cat expr.y
%left '+'
%left '*'

expr : expr BINOP expr
     | TOK_INTCON 

BINOP :  '+'  
      |  '*'
$ bison -v expr.y
expr.y: warning: 2 shift/reduce conflicts [-Wconflicts-sr]
1 op 2 op 3
 /  \
1    op
    /  \
   2    3
   /  \
  op    3
 /  \
1    2
$ cat expr-repaired.y
%left '+'
%left '*'

expr : expr '+' expr
     | expr '*' expr
     | TOK_INTCON 
$ bison -v expr-repaired.y
State 6

    1 expr: expr . '+' expr
    1     | expr '+' expr .
    2     | expr . '*' expr

    '*'  shift, and go to state 5

    $default  reduce using rule 1 (expr)

Basic PHP like interpreter using flex and bizon. Reduce/reduce and shift/reduce conflicts

By : user1417250
Date : March 29 2020, 07:55 AM
Hope this helps The basic issue leading to the conflicts is your handling of commands. Your intention is to define commands as zero or more commands, which is written as follows:
code :
commands: %empty
        | commands command
commands: command
        | commands command
switch_block: switch_stm commands
if_block: if_stm commands
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