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Using Javascript to write a function which compares two trees and returns true if they are equal in structure and in val

By : Srikanth Chilivery
Date : October 17 2020, 06:10 AM
I hope this helps you . It think its just like comparing two objects. You can create your own function which compare two nested objects using recursion.
code :
var a = {val: 1, left: null, right: null};
  var b = {val: 1, left: null, right: null};
  var c = {val: 2, left: null, right: null};

function compObj(a,b){
  if(typeof b !== "object" && b !== null) return false;
  if(Object.keys(a).length === Object.keys(b).length){
    for(let key in a){
      if(typeof a[key] === "object" && a[key] !== null){
        let temp = compObj(a[key],b[key]);
        if(!temp) return false;
      if(a[key] !== b[key]) return false;
    return true;
  return false;


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Write a function that compares two strings and returns a third string containing only the letters that appear in both

By : user1687429
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , That's fine for a first approach, but you can make a few improvements, and there's a small error.
If b contains a character in a that's already in c, you'll repeat it. To avoid repeats, you might consider using a Set to store the characters, since a Set won't have repeats. Assembling strings with += concatenation is usually inefficient; consider using a StringBuilder or an analogous string-assembly class. Your variable names aren't very descriptive. If a or b are empty, you don't have to do any work at all! Just return an empty string.

Engineered bool compares equal to both true and false, why?

By : user2569689
Date : March 29 2020, 07:55 AM
will be helpful for those in need Found this in the C++ standard, section 3.9.1 "Fundamental types" (note the magic footnote 42):
code :
6. Values of type bool are either true or false. 42)

Writing a function which compares two trees and returns true if they are equal in structure and in value and false other

By : Dimple
Date : March 29 2020, 07:55 AM
I wish did fix the issue. Given two trees, I want to return true if they are equal in structure and in value and false otherwise. , First, let's fix the syntax/logic errors:
code :
while a,b = for_check.shift
while (a, b = for_check.shift)
for_check << [a, b]   
for_check = [a, b]   
class TreeNode
  attr_accessor :val, :left, :right

  def initialize val, left = nil, right = nil
    @val = val
    @left = left
    @right = right

def binary_tree_compare a, b
  return !a && !b if !a || !b
  return false if a.val != b.val
  return binary_tree_compare(a.left, b.left) &&
         binary_tree_compare(a.right, b.right)

a = TreeNode.new(
  1, TreeNode.new(
    2, TreeNode.new(4)
  ), TreeNode.new(3)
b = TreeNode.new(
  1, TreeNode.new(
    2, TreeNode.new(4)
  ), TreeNode.new(3)

puts binary_tree_compare a, b

How do i write a function in JavaScript that compares two trees defined by TreeNodes a and b?

By : Klauss
Date : March 29 2020, 07:55 AM
Hope this helps Solution to my own question after serious research is shown in the snippet below.
code :
function compare(a, b){
  if (!a && !b) {
      return true;
   } else if (!a || !b) {
      return false;
   } else {
      return a.val === b.val && compare(a.left, b.left) && compare(a.right, b.right);

I want to write a function that returns True if all items in a list are equal

By : hktaylan
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , You can convert the list of integers to a set and check if the length of the set is 1:
code :
def is_same(lst):
    return len(set(lst)) == 1
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