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move overlap images over one another to get accurate difference

By : Halmat A. Hamadameen
Date : October 17 2020, 06:10 AM
I hope this helps you . It seems you are doing some defect detection task. The first solution comes in my mind is the image registration technique. First try to take the images in the same conditions (lighting, camera angle and ...) (one of your provided images is bigger 2 pixels).
Then you should register two images and match one to the other one, like this
code :
import cv2
import numpy as np


def alignImages(im1, im2):
    # Convert images to grayscale
    im1Gray = cv2.cvtColor(im1, cv2.COLOR_BGR2GRAY)
    im2Gray = cv2.cvtColor(im2, cv2.COLOR_BGR2GRAY)

    # Detect ORB features and compute descriptors.
    orb = cv2.ORB_create(MAX_FEATURES)
    keypoints1, descriptors1 = orb.detectAndCompute(im1Gray, None)
    keypoints2, descriptors2 = orb.detectAndCompute(im2Gray, None)

    # Match features.
    matcher = cv2.DescriptorMatcher_create(cv2.DESCRIPTOR_MATCHER_BRUTEFORCE_HAMMING)
    matches = matcher.match(descriptors1, descriptors2, None)

    # Sort matches by score
    matches.sort(key=lambda x: x.distance, reverse=False)

    # Remove not so good matches
    numGoodMatches = int(len(matches) * GOOD_MATCH_PERCENT)
    matches = matches[:numGoodMatches]

    # Draw top matches
    imMatches = cv2.drawMatches(im1, keypoints1, im2, keypoints2, matches, None)
    cv2.imwrite("matches.jpg", imMatches)

    # Extract location of good matches
    points1 = np.zeros((len(matches), 2), dtype=np.float32)
    points2 = np.zeros((len(matches), 2), dtype=np.float32)

    for i, match in enumerate(matches):
        points1[i, :] = keypoints1[match.queryIdx].pt
        points2[i, :] = keypoints2[match.trainIdx].pt

    # Find homography
    h, mask = cv2.findHomography(points1, points2, cv2.RANSAC)

    # Use homography
    height, width, channels = im2.shape
    im1Reg = cv2.warpPerspective(im1, h, (width, height))

    return im1Reg 
if __name__ == '__main__':

  # Read reference image
  refFilename = "vv9gFl.jpg" 
  imFilename =  "uP3CYl.jpg" 
  imReference = cv2.imread(refFilename, cv2.IMREAD_COLOR) 
  im = cv2.imread(imFilename, cv2.IMREAD_COLOR) 

  # Registered image will be resotred in imReg. 
  # The estimated homography will be stored in h. 
  imReg = alignImages(im, imReference)

  # Write aligned image to disk. 
  outFilename = "aligned.jpg" 
  cv2.imwrite(outFilename, imReg) 
b = cv2.imread("vv9gFl.jpg", 0 )
b = b[:, :280]

print (alined.shape)
print (b.shape)

diff = cv2.absdiff(alined, b)
cv2.imwrite("diff.png", diff)

threshold = 25
alined[np.where(diff >  threshold)] = 255
alined[np.where(diff <= threshold)] = 0

cv2.imwrite("threshold.png", diff) 

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Move rectangles so they don't overlap

By : Sean Mira
Date : March 29 2020, 07:55 AM
it helps some times You could use a greedy algorithm. It will be far from optimal, but may be "good enough". Here is a sketch:
code :
 1 Sort the rectangles by the x-axis, topmost first. (n log n)
 2 for each rectangle r1, top to bottom
       //check for intersections with the rectangles below it.
       // you only have to check the first few b/c they are sorted 
 3     for every other rectangle r2 that might intersect with it 
 4         if r1 and r2 intersect //this part is easy, see @Jose's answer
 5             left = the amount needed to resolve the collision by moving r2 left
 6             right = the amount needed to resolve the collision by moving r2 right
 7             down = the amount needed to resolve the collision by moving r2 down

 8             move r2 according to the minimum value of (left, right down)
               // (this may create new collisions, they will be resolved in later steps)
 9         end if

10     end
11 end

How to make the scroll bar to move to a accurate place

By : user2049453
Date : March 29 2020, 07:55 AM
it fixes the issue The problem with your code is that you are getting the offset of each element as you scroll down the list.
Offset is:
code :
The .offset() method allows us to retrieve the current position of an element
relative to the document.
var myID = $(".list").children().first().attr("id");

function next() {
    var li = $("#"+myID);
    $(".list li").css("background", "grey");
    var offset = parseInt(li.height())+parseInt(li.css("margin-top"));
    $('.list').animate({scrollTop: offset*(myID-1)},'slow');
    $("#"+myID).css("background", "red");
var myID = $(".list").children().first().attr("id");
var inc = 1;

function next() {
    var li = $("#"+myID);
    $(".list li").css("background", "grey");
    var offset = parseInt(li.height())+parseInt(li.css("margin-top"));
    $('.list').animate({scrollTop: offset*(inc-1)},'slow');
    $("#"+myID).css("background", "red");
    myID = $("#"+myID).next().attr("id");

How do I move div so they don't overlap

By : Nour Nabhan
Date : March 29 2020, 07:55 AM
should help you out You should be able to make the z-index for the button, or its container, a higher number to elevate it above the other div.

How to skip overlap intervals in the following query to get the accurate per day track time

By : niklr
Date : March 29 2020, 07:55 AM
it should still fix some issue This is a "gaps and islands" problem. I faked my own test data (since you didn't provide any), but I think it works. The key intuition is that all values within the same "island" (that is, contiguous time interval) will have the same difference from a row_number() column. If you want a little insight into it, do a raw select from the IntervalsByDay cte (as opposed to the subquery I have now); this will show you the islands calculated (with start and end points).
edit: I didn't see that you had a fiddle on the first go around. My answer has been changed to reflect your data and desired output
code :
with i as (
    select datediff(minute, '2013-01-01', StartTime) as s,
        datediff(minute, '2013-01-01', EndTime) as e
    from #track
), brokenDown as (
    select distinct n.Number
    from i
    join dbadmin.dbo.Numbers as n
        on n.Number >= i.s
        and n.Number <= i.e
), brokenDownWithID as (
    select Number, Number - row_number() over(order by Number) as IslandID,
        cast(dateadd(minute, number, '2013-01-01') as date) as d
    from brokenDown
), IntervalsByDay as (
        dateadd(minute, min(number), '2013-01-01') as [IntervalStart],
        dateadd(minute, max(number), '2013-01-01') as [IntervalEnd],
        max(Number) - min(Number) + 1 as [NumMinutes]
    from brokenDownWithID
    group by IslandID, d
select d, sum(NumMinutes) as NumMinutes
from IntervalsByDay
group by d
order by d

Algorithm for accurate detection of overlap between a square and a circle?

By : nomadics
Date : March 29 2020, 07:55 AM
Hope that helps I am implementing (in C++) a method to detect when an overlap is occurring between two static, axis-aligned shapes on a 2d plane. The shapes are either squares or circles, and therefore there are three cases I need to consider for overlap: square-square, circle-circle, and circle-square. , Here's a simple and fast algorithm:
code :
bool doesSquareCircleOverlap(float squareCenterX, float squareCenterY, float squareHalfSize, float circleCenterX, float circleCenterY, float circleRadius) {
    float x = fabs(circleCenterX - squareCenterX) - squareHalfSize;
    float y = fabs(circleCenterY - squareCenterY) - squareHalfSize;

    if (x>0) {
        if (y>0) {
            return x*x + y*y<circleRadius*circleRadius;
        } else {
            return x<circleRadius;
    } else {
        return y<circleRadius;
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