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gdscript global variable value not changing after get_tree().reload_current_scene()


gdscript global variable value not changing after get_tree().reload_current_scene()

By : Vipin
Date : October 17 2020, 06:10 AM
I wish this help you Building on an answer from a different site where i posted the question as well.
After creating the singleton globals where first_playthrough is declared, i replaced all instances of the variable on the script into globals.first_playthrough.
code :

    extends Node

    # removed the declaration here already, since it's already declared in globals.gd

    func _ready():
      # this is here so it will show the message
      first_playthrough_checker()

    func first_playthrough_checker():
      # message below doesn't show anymore after globals.first_playthrough becomes false.
      if globals.first_playthrough:
        text_printer("Hello from Number Guesser!\n\n")

    func _restart_game():
      #I haven't tested it but i suspect the line after reloading the scene will create a memory leak?
      #So i changed globals.first_playthrough's value before reloading the scene instead.
      globals.first_playthrough = false
      get_tree().reload_current_scene()


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Python: changing global variable and global list elements inside a function

Python: changing global variable and global list elements inside a function


By : elmuria
Date : March 29 2020, 07:55 AM
it fixes the issue Use global variable:
code :
verifier = 0

def newlist():
    if verifier == 0:
        return ["A","B","C","D","E","F","G","H","I"]
    elif verifier == 1:
        return ["0","1","2","3","4","5","6","7","8"]

print newlist()

def main():
    global verifier
    verifier = 1
main()

print newlist()
verifier = 0
letters = ["A","B","C","D","E","F","G","H","I"]
if verifier == 0:
    letters = ["A","B","C","D","E","F","G","H","I"]
elif verifier == 1:
    letters = newlist()
def newlist(verifier):
    if verifier == 0:
        return ["A","B","C","D","E","F","G","H","I"]
    elif verifier == 1:
        return ["0","1","2","3","4","5","6","7","8"]

def main():
    print newlist(0)
    print newlist(1)
main()
letters = {
    0: ["A","B","C","D","E","F","G","H","I"],
    1: ["0","1","2","3","4","5","6","7","8"]
}

print letters.get(0, None)
Why is function not changing global variable even after specifying global

Why is function not changing global variable even after specifying global


By : user5698917
Date : March 29 2020, 07:55 AM
around this issue startup does not store an expression, it stores the result of an expression, once.
In other words, the variable startup references the result of 50 + addon, which at the time is the integer 70.
code :
startup = lambda: 50 + addon
def click():
    global addon
    addon *= 2
    print addon, startup()
Changing a global variable in a function without using global keyword

Changing a global variable in a function without using global keyword


By : Jayshree
Date : March 29 2020, 07:55 AM
I hope this helps you . You need the global keyword when you want to rebind the global variable to a different object. But you don't need it if all you want to do is change a mutable object. In your case L is a list and can be mutated in place with a slice operation L[:] = k. To demonstrate:
code :
>>> L = [1,2,3]
>>> 
>>> def L_value_Change(k):
...     L[:] = k
... 
>>> old_id = id(L)
>>> L
[1, 2, 3]
>>> L_value_Change([4,5,6])
>>> assert id(L) == old_id
>>> L
[4, 5, 6]
>>> 
How can I change a local variable assigned to the value of a global one without changing the global variable?

How can I change a local variable assigned to the value of a global one without changing the global variable?


By : Cá Bống Mải Chơi
Date : March 29 2020, 07:55 AM
I wish this help you So this is basically how the code works that I'm using. , The problem here is the following line:
code :
Lvar = Gvar
Lvar = Gvar[:]
global Gvar
Gvar = ["Hello"]

def someFunction():
    Lvar = Gvar[:]
    Lvar.append("World")
    print(Lvar)
    print(Gvar)

someFunction()
Append a number to a variable name in GDScript

Append a number to a variable name in GDScript


By : Emre
Date : March 29 2020, 07:55 AM
Does that help If all your themes share the same exact structure, you can do something similar to what Christopher Bennett proposes. Another option that may give you more flexibility, at the expense of possibly more repetition, is something like this:
code :
# Defined at class level
const THEMES = [
    # Theme 1
    {
        tileset = 'tileset_1',
        NPC_mid_boss = 'folder_1/mid_boss',
        NPC_end_boss = 'folder_1/end_boss',
        # ...
    },
    # Theme 2
    {
        tileset = 'tileset_2',
        NPC_mid_boss = 'folder_2/mid_boss',
        NPC_end_boss = 'folder_2/end_boss',
        # ...
    },
    # ...
]


func my_func():
    # Pick a random theme
    var theme = THEMES[randi() % THEMES.size()]
    tileset_to_use = theme.tileset
    # ...
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