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How to use dot notation after +


How to use dot notation after +

By : Olexandr Grasymenko
Date : October 17 2020, 06:10 PM
seems to work fine I have JSON data in another file, I am accessing that from a module file. I am using a loop to get lots of data easily but I am stuck on a problem. When using dot notation it goes cars.c1.name, but in my example it is cars.c+i+.. and then it stops because I don't know how to add .name to that. , here is what's wrong with what you are doing:
code :
const carName = cars.c+i+.name; // not working
const carName = cars["c"+ i].name;


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Difference between big-O notation and theta notation, why (theta) Ө-notation is suitable to insertion sort to describe i

Difference between big-O notation and theta notation, why (theta) Ө-notation is suitable to insertion sort to describe i


By : Heath Burnett
Date : March 29 2020, 07:55 AM
To fix this issue We use Ө-notation to write worst case running time of insertion sort. But I’m not able to relate properties of Ө-notation with insertion sort, why Ө-notation is suitable to insertion sort. How does the insertion sort function f(n), lies between the c1*n^2 and c2*n^2 for all n>=n0. , The use of Ө-notation :
code :
suppose we have a function , 
                  f(n) = 4logn + loglogn  
             we can write this function as 
                  f(n) = Ө(logn)
             Because its upper bound and lower bound
are O(logn) and  Ω(logn) repectively, which are same 
so it is legal to write this function as , 
                  f(n)=  Ө(logn)
     **Finding upper bound :**

 f(n) = 4logn+loglogn


    For all sufficience value of n>=2

        4logn <= 4 logn   
        loglogn <= logn 

    Thus , 

     f(n) = 4logn+loglogn <= 4logn+logn
                          <= 5logn
                           = O(logn)       // where c1 can be 5 and n0 =2
**Finding lower bound :**

   f(n) = 4logn+loglogn

   For all sufficience value of n>=2

      f(n) = 4logn+loglogn >= logn
    Thus,              f(n) =  Ω(logn)   // where c2 can be 1 and n0=2


  so , 
                        f(n) = Ɵ(logn) 
If running time of insertion sort is described by simple function f(n).
In particular , if f(n) = 2n^2+n+1 then 

Finding upper bound:
      for all sufficient large value of n>=1
                         2n^2<=2n^2   ------------------- (1)
                           n <=n^2    --------------------(2)
                           1 <=n^2    --------------------(3)
        adding eq 1,2 and 3, we get.
                     2n^2+n+1<= 2n^2+n^2+n^2
        that is 
                         f(n)<= 4n^2
                         f(n) = O(n^2)  where c=4 and n0=1 

Finding lower bound:
       for all sufficient large value of n>=1
                           2n^2+n^2+1 >= 2n^2
         that is , 
                                f(n) >= 2n^2
                                f(n) = Ω(n^2) where c=2 and n0=1     
      because upper bound and lower bound are same,
                                f(n) = Ө(n^2)


   if f(n)= 2n^2+n+1 then, c1*g(n) and c2*g(n) are presented by diagram:
How to convert big negative scientific notation number into decimal notation string in javascript?

How to convert big negative scientific notation number into decimal notation string in javascript?


By : man xiao
Date : March 29 2020, 07:55 AM
like below fixes the issue This works for any positive or negative number with the exponential 'E', positive or negative. (You can convert a numerical string to a number by prefixing '+', or make it a string method, or a method of any object, and call the string or number.)
code :
Number.prototype.noExponents= function(){
    var data= String(this).split(/[eE]/);
    if(data.length== 1) return data[0]; 

    var  z= '', sign= this<0? '-':'',
    str= data[0].replace('.', ''),
    mag= Number(data[1])+ 1;

    if(mag<0){
        z= sign + '0.';
        while(mag++) z += '0';
        return z + str.replace(/^\-/,'');
    }
    mag -= str.length;  
    while(mag--) z += '0';
    return str + z;
}

var n=2.54E-20;
n.noExponents();
"0.0000000000000000000254"
What is the difference between array notation and object notation when creating multiple chunks in webpack?

What is the difference between array notation and object notation when creating multiple chunks in webpack?


By : Giri Shankar
Date : March 29 2020, 07:55 AM
To fix this issue If you just want to specify several chunks you can just add hot-loading script to one of them:
code :
entry: {
    vandor: './vendor/vendor.js',
    app: ['webpack-hot-middleware/client', './src/js/entry.js']
},
entry: {
    vandor: ['./vendor/vendor.js'],
    app: ['./src/js/entry.js']
},
...
webpackConfig.entry.app.unshift('webpack-hot-middleware/client');
How do I replace array-style notation in templates with object-notation when switching from cakephp 2.x to 3.x

How do I replace array-style notation in templates with object-notation when switching from cakephp 2.x to 3.x


By : Dmytro Melnyk
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further When migrating, what is a fast way to replace the array notation of cakephp 2.x , this regular expression works: find this
code :
\$order\['(\w+)'\]
$order->\1
\$offcut->$1
Prevent Jupyter from switching between normal mathematical notation and scientific notation

Prevent Jupyter from switching between normal mathematical notation and scientific notation


By : user3701457
Date : March 29 2020, 07:55 AM
around this issue I want to ask a question about turning off scientific notation of numbers in Jupyter notebook. , This is a numpy print issue:
code :
In [544]: with np.printoptions(suppress=True): 
     ...:     np.array([[1.63276953e+02, 1.41858314e-01], 
     ...:    [1.64042353e+02, 5.13131094e-01]]) 
     ...:                                                                                      
In [545]: with np.printoptions(suppress=True): 
     ...:    print( np.array([[1.63276953e+02, 1.41858314e-01], 
     ...:    [1.64042353e+02, 5.13131094e-01]])) 
     ...:     
     ...:                                                                                      
[[163.276953     0.14185831]
 [164.042353     0.51313109]]

In [546]: with np.printoptions(suppress=False): 
     ...:    print( np.array([[1.63276953e+02, 1.41858314e-01], 
     ...:    [1.64042353e+02, 5.13131094e-01]])) 
     ...:     
     ...:                                                                                      
[[1.63276953e+02 1.41858314e-01]
 [1.64042353e+02 5.13131094e-01]]
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