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Returning a reference to a class data member and then trying to change that member

By : Nicholas A E
Date : October 17 2020, 06:10 PM
this one helps. I've seen other posts on this but didn't really get what happens yet. , When you store the result in int n you create a copy. Try:
code :
int &n = s1.get();

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Returning a reference from a Class member?

By : Sandy Jeakins
Date : March 29 2020, 07:55 AM
wish helps you You're using $this->template_compile_path; to initialize Smarty. Have you initialized this? On a different note have you set PHP to display errors? Have you looked in your web server error log?
If you have a doubt about what a function returns use print_r on the result.

move ctor of class with a constant data member or a reference member

By : Ayse Kubra
Date : March 29 2020, 07:55 AM
I hope this helps you . I have some problems understanding when and if the move constructor or move assignment operator are invoked, in particular in the context of a class with constant data member. Consider the class
code :
A<B> a = b.get_a();

C++: Returning a member variable by reference in member function

By : Max Raj
Date : March 29 2020, 07:55 AM
With these it helps You are making a copy.
The function get does indeed return a reference, but you are assigning it by-value:
code :
HeavyClass foo = HeavyClass::get(); // critical line
const HeavyClass& foo = HeavyClass::get()

When returning a private member, is the returned value a direct reference to the member or a separate copy?

By : Jeremiah Grossman
Date : March 29 2020, 07:55 AM
I wish this helpful for you To clarify this, consider the following code: ,
is the original private member within foo mutated?
code :
public class Baz {
    public int x = 0;

public class Foo {
    private Baz thing;

    public Foo() { thing = new Baz(); }

    public Baz getThing() {
        return this.thing;

public class Bar {
    public Bar() { ... }

    public Object makeNewThing() { ... }

    public void changeThing() {
        Foo foo = new Foo();
        Baz thing = foo.getThing();
        thing.x = 10;
        System.out.println(foo.thing); // this will print 10, not 0

c++ const member function returning reference to class member

By : Naomi
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further When you declare a function const, you are saying that this is a function that is permitted on both a non-const and const instance of the object. Because it can be invoked on a const instance, the function should not mutate the object. When you return a non-const reference to an internal object, you are providing the caller with a way of mutating the object's internal state indirectly. To fix this, return a constant object, instead.
In other words, instead of:
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