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How to find if the row is part of index?


By : Ram Manohar Sharma
Date : October 17 2020, 06:10 PM
hope this fix your issue
my total rows in the table is 1,45,454 but the cardinality of the all the indexes are 1,45,300
code :


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Clustered index - multi-part vs single-part index and effects of inserts/deletes


By : user2022729
Date : March 29 2020, 07:55 AM
help you fix your problem Yes, inserting into the middle of an existing table (or its page) could be expensive when you have a less than optimal clustered index. Worst case would be a page split : half the rows on the page would have to be moved elsewhere, and indices (including non-clustered indices on that table) need to be updated.
You can alleviate that problem by using the right clustered index - one that ideally is:

How to find numpy.argmax() on part of list and save index?


By : GitGing
Date : March 29 2020, 07:55 AM
wish help you to fix your issue The simple approach would be to, I dunno, just add a 4 to the output? Assuming it isn't always 4, you could always do this:
print np.argmax(array[x : 8]) + x

How to find index of an array when I know only part of string?


By : idk
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , Use foreach() to make an iteration over the array and strpos() for searching your needle in the elements of the array.
code :
$array = [0 => 'blue pants', 1 => 'red pants', 2 => 'green pants', 3 => 'green pants'];

foreach ($array as $key => $value) {
    if (strpos($value, 'red') !== false) {
        echo "Key={$key}, Value: {$value}";
        break;
    }
}

How to find if a specific letter is a part of a word, and how to get its index?


By : SHIVAM GOEL
Date : March 29 2020, 07:55 AM
hop of those help? Think about it - in your second case, you always return 0. You need instead to keep track of how many characters you've had already, i.e. how many recursions:

Find element index containing given string part


By : rcombies
Date : March 29 2020, 07:55 AM
help you fix your problem If ES6 is not a problem, you can use array.prototype.findIndex and string.prototype.includes:
code :
var myArray =["apple","banana","cherry"];
var search= "nana";
var index = myArray.findIndex(el => el.includes(search));
console.log(index);
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