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Why does a private struct defined in a .h require a scope in a return type in the .cpp file?


Why does a private struct defined in a .h require a scope in a return type in the .cpp file?

By : masharul
Date : October 17 2020, 06:10 PM
To fix this issue Until you reach A::foo in the function definition you are in the the scope of where the function is begin defined. Since you are not in the class scope, B is not in scope and results in a compiler error.
You have to use A:: to tell the compiler where B is located. Once you reach A::foo you are now in the scope of A again and it is not needed. One thing you can do is to use a trailing return type to put the return in the class scope like
code :
auto A::foo() -> B { ... }


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Typescript error : Property defined as private on type Class is defined as public on type Interface

Typescript error : Property defined as private on type Class is defined as public on type Interface


By : Prateek
Date : March 29 2020, 07:55 AM
should help you out You can't have the private access modifier on the getUserInfo function on the Service class as it's declared on the interface IService.
If the class is a IService, it needs to have all of the functions/properties of the interface declared publicly.
code :
module App.Services {

    export class Service implements App.Interfaces.IService {

        /* private <= remove */ getUserInfo(): void { }

    }   
}
Return a Struct defined in a separate header file: unknown type name

Return a Struct defined in a separate header file: unknown type name


By : Tuskaugur
Date : March 29 2020, 07:55 AM
I hope this helps you . The solution that worked for me might be Tizen related, since I haven't seen any post with this solution before on Stack Overflow (and Tizen is not that common). If anyone could confirm or deny that would be great.
Anyways, the solution that my friend came up with was to add 'FileName::' in front of the return type of the function specified in FileName.cpp (not necessary in FileName.h) The complete solution is posted below with highlights of what fixed the problem (line 3 in FileName.cpp).
code :
1.  typedef struct StructName {
2.      int hello;
3.      int there;
4.      int friend;
5.      Foo(int num) : hello(99), there(25) {
6.          friend = num;
7.      }
8.  } StructName;
9.
10. virtual StructName FunctionName(void);
1.  #include FileName.h
2.
3.  FileName::StructName FunctionName(void) { // <- Adding 'FileName::' infront of
4.      int n = 5;                            // the return type fixed the problem
5.      StructName s(n);
6.      return s;
7.  }
Private struct as a return type of a public method

Private struct as a return type of a public method


By : N. Shah
Date : March 29 2020, 07:55 AM
Does that help If a method returns a type, then that type needs to be "as visible" as the method itself.
This is simply because the consuming code needs to be able to understand the object being returned. Whether it's a class or struct makes no difference in this regard. C# is a statically typed language and so the compiler needs to be able to guarantee that any code which consumes that method will be aware of the return type.
How to set the Return Type of a Class Member Function as the object of a Private Struct

How to set the Return Type of a Class Member Function as the object of a Private Struct


By : Help Me Please
Date : March 29 2020, 07:55 AM
help you fix your problem sorry for the long and confusing title, but I couldn't think of a better way to ask this. So, what I have is a class: , The syntax for that needs to be:
code :
template <typename T>
Set<T>::Node* Set<T>::r_add(Node *temp)
{
    return temp;
}
template <typename T>
auto Set<T>::r_add(Node *temp) -> Node*
{
    return temp;
}
How to type hint a return value that's defined in the function's local scope?

How to type hint a return value that's defined in the function's local scope?


By : user1261772
Date : March 29 2020, 07:55 AM
Hope this helps Here's what I could think of from a quick scan of the docs. This isn't a good solution at all (I think), but it should do the job for you.
There's something called typing.TypeVar (docs). Its basically a generic type. So what you could possibly do is:
code :
from typing import TypeVar
B = TypeVar('B', bound=A)
def foo(spam: bool) -> B:
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