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Python dictionary is splitting string keys by character

By : Oswaldo Mena
Date : October 18 2020, 06:10 AM
wish of those help fromkeys expects an iterable of keys that is uses to build the dictionary. You're providing it a single key at a time, which it is interpreting as an iterable of characters.
You can set up a generator expression to process the file names into the keys, and then give that generator to fromkeys:
code :
processed_names = (name.split('.')[0] for name in done_match)
d = dict.from_keys(processed_names, 1)

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splitting a dictionary in python into keys and values

By : Ilya Khomutov
Date : March 29 2020, 07:55 AM
will help you How can I take a dictionary and split it into two lists, one of keys, one of values. For example take: , Not that hard, try help(dict) in a console for more info :)
code :
keys = dictionary.keys()
values = dictionary.values()
items = dictionary.items()
keys, values = zip(*dictionary.items())

Create a pandas dataframe from a python dictionary. Python dictionary has multiple keys and its values have both string

By : user3686349
Date : March 29 2020, 07:55 AM
will be helpful for those in need You can first load your dict to a Series and then convert it to a DataFrame, keep appending to a df list, finally use pd.concat to merge your DFs.
code :
df_list = []
pd.concat(df_list).set_index('key1', drop=False).rename_axis('')

    key1    key2    key3
abc abc     True    []
def def     True    [a, b, c]

Python: Splitting a long string by character for input into dictionary

By : Lalit Khurana
Date : March 29 2020, 07:55 AM
help you fix your problem I am importing a file into a dictionary. The file is organized with lines like this: , maybe something like:

Python: dictionary comparisons in splitting lists by first character

By : Gurran
Date : March 29 2020, 07:55 AM
help you fix your problem Here is the exercise that is stumping me:

Python: splitting dictionary into smaller dictionaries by keys (tuple)

By : F. Furlanetti
Date : March 29 2020, 07:55 AM
This might help you You can use collections.defaultdict, iterate and update keys determined by the bucket boundaries. This is a better idea than creating a variable number of variables.
code :
d = {(0, 2): 1, (0, 4): 2, (0, 10): 3, (0, 3): 4,
     (0, 11): 5, (0, 20): 6, (0, 8): 7, (0, 14): 8}

L = [0, 5, 10, 15, float('inf')]  # include infinite to facilitate later comparisons

from collections import defaultdict

dd = defaultdict(dict)

for k, v in d.items():
    for i, j in zip(L, L[1:]):
        if i <= k[1] < j:
            dd[i].update({k: v})


            {0: {(0, 2): 1, (0, 3): 4, (0, 4): 2},
             5: {(0, 8): 7},
             10: {(0, 10): 3, (0, 11): 5, (0, 14): 8},
             15: {(0, 20): 6}})
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