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System.lineSeparator() does not work in Linux environment


By : Zahurul Islam Islam
Date : October 18 2020, 06:10 AM
should help you out RFC 5322 describes the standard for email.
Per Section 2.1:
code :


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Maven and System.lineSeparator


By : Alexandr Kravchenko
Date : March 29 2020, 07:55 AM
will be helpful for those in need compilation as 1.5 means java code structure / class file design to be at level 1.5 - not to be confused with jdk code itself
If jdk 1.7 ships a rt.jar file with System.java code with some methods, javac compiler has no way to know what it was as of 1.6, 1.5, 1.4 level (unless you have classes.zip and specify the boot classpath)

System.lineSeparator() returns nothing


By : Haider Ali
Date : March 29 2020, 07:55 AM
this one helps. As you expect, the line separator contains special characters such as '\r' or '\n' that denote the end of a line. However, although they would be written in Java source code with those backslash escape sequences, they do not appear that way when printed. The purpose of a line separator is to separate lines, so, for example, the output of
code :
System.out.println("Hello"+System.lineSeparator()+"World");
Hello
World
Hello\nWorld
System.out.println("LineSeperator1: "+System.getProperty("line.separator"));
import org.apache.commons.lang3.StringEscapeUtils;

public class LineSeparators {
    public static void main(String[] args) {
        String ls1 = StringEscapeUtils.escapeJava(System.getProperty("line.separator"));
        System.out.println("LineSeperator1: "+ls1);
        String ls2 = StringEscapeUtils.escapeJava(System.lineSeparator());
        System.out.println("LineSeperator2: "+ls2);
    }
}
LineSeparator1: \n
LineSeparator2: \n
javac -cp commons-lang3-3.4.jar LineSeparators.java
java -cp commons-lang3-3.4.jar:. LineSeparators

Difference between \n and System.lineSeparator();?


By : Anu K
Date : March 29 2020, 07:55 AM
seems to work fine The \n character is a single character which is called "new line", usually. Sometimes it may be called "linefeed" to be more accurate. The line separator varies from computer to computer, from Operating System to Operating System. You will get different line separators on Windows and Unix.
If you run this: System.getProperty("line.separator") it will return the line separator that is specific to your OS. On windows it will return \r\n and on Unix it will return \n.

why is System.lineSeparator() deprecated?


By : Muhammad Suleman
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , The screenshot of my intelliJ IDE as I could not post a picture directly (by the way am using jdk 10) For some reason I need to output a String based on input and there might be new lines in the String. To make the program working on different platform I use a variable to store System.lineSeparator() and insert it when needed. But then I realized that intelliJ shows that it is deprecated. So my question is, why is this function deprecated? Is it a bad practice using line separators? What is the better way of doing this? ,
why is this function deprecated?

Is there a way to make System.lineSeparator() work in a JLabel string?


By : user3343224
Date : March 29 2020, 07:55 AM
hop of those help? Altough this question is already answered, i want to provide more background.
The official documentation states, that you are allowed to use plain HTML in most Swing components. You can find the full reference here. The most importants parts are:
code :
new JButton("<html>Line one<br>Line two</html>");
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